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nexus9112 [7]
4 years ago
9

ZOOM IN ON PICK

Mathematics
1 answer:
salantis [7]4 years ago
6 0

Answer:

C. The difference of the medians is 4 times the interquartile range.

Step-by-step explanation:

The diagram show two box plots.

<u>Mahoney's box plot:</u>

Median =33

Interquartile range =34-32=2

<u>Martin's box plot:</u>

Median =41

Interquartile range =42-40=2

The interquartile ranges are the  same.

The difference of the medians =41-33=8

Hence, the difference of the medians is 4 times the interquartile range.

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mestny [16]
Percentage of pages of a book read by Katie = 32%
Total number of pages of the book read by Katie = 80
Let us assume the number of pages that the book has = x
Then
(32/100) * x = 80
32x = 80 * 100
32x = 8000
x = 8000/32
   = 250
So the book has a total of 250 pages in it.
Then
The number of pages that Katie still needs to read = 250 - 80
                                                                                 = 170
So Katie needs to read 170 more pages in the book.

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Answer:

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Step-by-step explanation:

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QUESTION 8 The orthocenter of a triangle is formed by the ____________of a triangle. perpendicular bisectors angle bisectors med
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<span>The orthocenter of a triangle is formed by the ALTITUDES of a triangle.</span>

Source:
http://www.1728.org/trictr.htm


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\large\begin{array}{l} \textsf{You must add 1 to complete the square.}\\\\ \textsf{There is a very common special product: (square of a sum)}\\\\ \mathsf{(a+b)^2=a^2+2ab+b^2}\\\\\\ \textsf{Take the given equation:}\\\\ \mathsf{x^2+2x=-1\qquad(i)}\\\\\\ \textsf{The first term is a square (x squared)}\\\\ \textsf{The second term is a product of 2, x and 1.} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{We need to find a proper value for b, so that if we add it to}\\\textsf{the left side of the equation, we get a perfect square.}\\\\ \textsf{So,}\\\\ \begin{array}{cccccccccc} \mathsf{a^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{a}&\!\!\!\cdot\!\!\!&\mathsf{b}&\!\!\!+\!\!\!&\mathsf{b^2}&=\mathsf{(a+b)^2}\\\\ \mathsf{\downarrow}&&&\!\!\!\!\!&\downarrow&\!\!\!\!\!&\downarrow&&\downarrow\\\\ \mathsf{x^2}&\!\!\!+\!\!\!&\mathsf{2}&\!\!\!\cdot\!\!\!&\mathsf{x}&\!\!\!\cdot\!\!\!&\mathsf{1}&\!\!\!+\!\!\!&\mathsf{1^2}&=\mathsf{(x+1)^2} \end{array}\\\\\\ \textsf{Just by comparing the expressions above, we can conclude that}\\\textsf{b must be equal to 1, so we get a perfect square:}\\\\ \mathsf{(x+1)^2=x^2+2x+1} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{Back to (i), adding 1 to both sides:}\\\\ \mathsf{x^2+2x+1=-1+1}\\\\ \boxed{\begin{array}{c} \mathsf{(x+1)^2=0} \end{array}} \end{array}


\large\begin{array}{l}\\\\\\ \textsf{If you want to solve this equation for x, you will find}\\\\ \mathsf{x+1=0}\\\\ \mathsf{x=-1}\quad\longleftarrow\quad\textsf{(solution)} \end{array}


If you're having problems understanding the answer, try seeing it through your browser: brainly.com/question/2112248


\large\begin{array}{l} \textsf{Any doubt? Please, comment below.}\\\\\\ \textsf{Best regards! :-)} \end{array}

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