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alexgriva [62]
2 years ago
6

Suppose a city with population 100, 000 has been gromng at a rate of % per year. If this rate continues , find the population of

this city in 14 years.​
Mathematics
1 answer:
Eduardwww [97]2 years ago
8 0
What’s the percent????
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Cookies are being sold in the cafeteria to raise money for the cheerleaders. One giant cookie costs $1 while each one bought aft
sladkih [1.3K]

Answer:

y = 0.75x + 1

Step-by-step explanation:

Here, we want to write an equation in slope-intercept form to represent this information

Since $1 is the cost of 1 only, this represents our y intercept

It means if we are not interested in purchasing more than 1, our cost will be $1

Now, for each one bought after, we have a rate of $0.75 per one

Mathematically, that will be $0.75 times the number bought after

Hence. we have that;

y = 0.75x + 1

if 1, x = 0; so we have cost of 1 as $1

7 0
2 years ago
A newspaper reported that last weekend a movie earned $16.2 million. This was 68% of the previous weekend's earnings. Approximat
Serjik [45]

Answer:

$23.8 million

Step-by-step explanation:

w = previous weekends earnings

16.2 = .68w

x = 16.2/0.68

x = 23.8

6 0
2 years ago
Can soembody help me answer this please. PLEASE BE QUICK AND RIGHT !!!​
myrzilka [38]

Answer:

A, D, and G

Step-by-step explanation:

Let's try each of the answer choices, one by one.

A) Plug x = 2 into each expression and see what we get.

7x + 4 = 7 * 2 + 4 = 14 + 4 = 18

3x + 5 + 4x - 1 = 3 * 2 + 5 + 4 * 2 - 1 = 6 + 5 + 8 - 1 = 18

Since they're both 18 when x = 2, A is true.

B) The statement says that the expressions are <em>only </em>equal for x = 4 and x = 8, but as we saw from A, they're also equal when x = 2, so B is wrong.

C) Let's try to find a counterexample for this by plugging in an odd number into each expression, like 1:

7x + 4 = 7 * 1 + 4 = 7 + 4 = 11

3x + 5 + 4x - 1 = 3 * 1 + 5 + 4 * 1 - 1 = 3 + 5 + 4 - 1 = 11

We see that these two expressions are equivalent when x = 1, which is an odd number, so this contradicts the statement that they're <em>only</em> equal when x is even. C is wrong.

D) Let's combine like terms for the expression 3x + 5 + 4x - 1:

3x + 4x + 5 - 1 = 7x + 4

Notice that this is the exact same expression as the first one, which is 7x + 4 so that means for any x, these two expressions will always be the same. D is thus true.

E) This is not true because it's possible that two expressions aren't equivalent but have the same value for a certain odd number and a certain even number. E is incorrect.

F) Obviously, if the two expressions are equivalent, they will give the same answer for any input of x, including when x = 0, so F is wrong.

G) Again, the two expressions will always be equal, including when x = 8, so this statement is true.

The answers are A, D, and G.

Hope this helps!

4 0
3 years ago
Read 2 more answers
Question 95 pts
garri49 [273]
The correct answer is “hasn’t” probably maybe
5 0
2 years ago
he one‑sample t statistic from a sample of n = 23 observations for the two‑sided test of H 0 : μ = 15 versus H α : μ &gt; 15 has
DedPeter [7]

Answer:

t = 2.24

The first step is calculate the degrees of freedom, on this case:  

df=n-1=23-1=22  

Since is a one side right tailed test the p value would be:  

p_v =P(t_{(22)}>2.24)=0.01776  

And for this case we can conclude that:

0.01 < p_v < 0.025

And we will reject the null hypothesis at \alpha=0.025 since p_v < \alpha

Step-by-step explanation:

Data given and notation  

\bar X represent the mean height for the sample  

s represent the sample standard deviation

n=23 sample size  

\mu_o =15 represent the value that we want to test

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 15, the system of hypothesis would be:  

Null hypothesis:\mu \leq 15  

Alternative hypothesis:\mu > 15  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

For this case the statistic is given:

t = 2.24

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=23-1=22  

Since is a one side right tailed test the p value would be:  

p_v =P(t_{(22)}>2.24)=0.01776  

And for this case we can conclude that:

0.01 < p_v < 0.025

And we will reject the null hypothesis at \alpha=0.025 since p_v < \alpha

5 0
3 years ago
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