Answer:
1,757,600,000
Step-by-step explanation:
company consists of 3 letters followed by 5 numbers how many different account numbers are possible if repetitions of letters and digits are allowed.
We have 26 lettrs and 10 digits
So, the possible out comes for each one of the letters = 26
And the possible out comes for each one of the numbers = 10
∵ repetitions of letters and digits are allowed.
So, the possible accounts are = 26³ * 10⁵ = <u>1,757,600,000</u>
Let x = sue
and then let 3x-84 = marcia
therefore
(x)+(3x-84)=132
4x-84=132
4x=216
x=54
however just solving for x doesnt completely solve. it only shows sues money because x = sue
for marcia
3x-84
3(54)-84
162-84
78
therefore Marcia has 78$.
Step-by-step explanation:
∫₀³⁰ (r/V C₀ e^(-rt/V)) dt
If u = -rt/V, then du = -r/V dt.
∫ -C₀ e^u du
-C₀ ∫ e^u du
-C₀ e^u + C
-C₀ e^(-rt/V) + C
Evaluate between t=0 and t=30.
-C₀ e^(-30r/V) − -C₀ e^(-0r/V)
-C₀ e^(-30r/V) + C₀
C₀ (-e^(-30r/V) + 1)
I got the same answer. Try changing the lowercase v to an uppercase V.
Answer:
1. 3sqrt(2)
Choice C
2. 2sqrt(3)
Choice D
Step-by-step explanation:
1. sqrt(x+3)
sqrt(15+3)
sqrt(18)
sqrt(9*2)
sqrt(9)sqrt(2)
3sqrt(2)
Choice C
2. 6/sqrt(x)
6/sqrt(3)
no radicals in the denominator, multiply by 1 in the form of the radical
6/sqrt(3) * sqrt(3)/sqrt(3)
6sqrt(3)/ (sqrt(3)*sqrt(3))
6sqrt(3)/3
2sqrt(3)
Choice D
8000 is 80*100. Use a calculator if you can't solve this in your head. c:
