The solution of the given system of equation is x = -3 and y = 4 respectively.
<h3>What is a system of linear equations?</h3>
A system of linear equations can be defined as a number of equations needed to solve the equations. For n number of variables n number of equations are required.
The given system of equations is as,
y = 4x + 16 (1)
y = −2x − 2 (2)
In order to solve them, substitute equation (2) into (1) as follows,
4x + 16 = −2x − 2
=> 4x + 2x = -2 - 16
=> 6x = -18
=> x = -3
Then, y = -2 × -3 - 2 = 4
Hence, the solution of the given system of equation is x = -3 and y = 4.
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Answer:
Step-by-step explanation:
=8x + (-3) (5) + (-3) (9x)
=8x + -15 + -27x
=8x + -15 + -27x
(8x + -27x) + (-15)
19x +-15
19x -15
(2^8 x 3^-5 x 6^0) x [(3^-2/2^3) x 2^28] = x
(256 x .004 x 1) x [(.111/8) x 268,435,456] = x
(1.024 x 1) x .(0138 x 268,435,456) = x
1.024 x (.0138 x 268,435,456) = x
1.024 x 3,704,409.2928 = x
3,793,315.1158272 = x
Correct me if I am wrong. :)
Answer:
C
Step-by-step explanation:
From the given coordinates
A(6, 0), B(0, 0) then AB = 6 - 0 = 6
B(0, 0), C(0, 8) then BC = 8 - 0 = 8
To calculate AC use Pythagoras' theorem on the right triangle formed
AC² = AB² + BC² = 6² + 8² = 36 + 64 = 100
Take the square root of both sides, hence
AC = 
= 10
Perimeter = AB + BC + AC = 6 + 8 + 10 = 24 → C
