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vivado [14]
3 years ago
9

1. En una investigación sobre el ADN de una especie animal se ha encontrado que del total de bases nitrogenadas un 30% correspon

de a adenina. ¿Cuáles son los porcentajes de las demás bases?
Biology
1 answer:
pshichka [43]3 years ago
5 0

Answer:

Adenina (30%), citosina (15%), guanina (15%) o timina (40%)

Explicación:

El 30% de las bases nitrogenadas totales lo ocupa la adenina, el 15% de las bases nitrogenadas totales corresponde a la citosina, el 15% de las bases nitrogenadas totales toma la guanina y el 40% restante de las bases nitrogenadas totales lo ocupa la timina. Entonces, al combinar todos estos porcentajes, obtenemos el 100 por ciento del volumen del ácido desoxirribonucleico (ADN).

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pantera1 [17]
I think D is the right answer.
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Proteins help to build and repair body tissues. *<br> True<br> False<br><br> pls help quick
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Read 2 more answers
Suppose that in unicorns, two autosomal loci interact to determine the type of tail. One locus controls whether a tail is presen
Nina [5.8K]

Explanation:

As you can see in the picture below, this is a dihybrid cross with a twist.

We can accomplish that mutually parentages are heterozygotes for both characters because the genotypes are  

9 unicorns with curly tails (shown in green)

3 with straight tails (shown in red)

3  curly tales trait carriers with no tail (shown in dark blue)

1  straight tail trait carriers with no tail ( shown in light blue)

If this was an ordinary case of the dihybrid cross, we would get a 9:3:3:1 phenotype ratio.

However, since the first trait, the presence of the tail, is affecting the other trait, the trait texture, the ratio is altered.

\frac{1}{4} of the offspring (genotypes tt C_   and tt SS) has no tail, therefore we cannot observe the texture of the tail (some of the tailless individuals have Curly alleles -blue squares marked with green, some of them have Straight alleles -blue square marked with red ).

Therefore, the altered ratio is  \frac{1}{2} curly tails,\frac{1}{4} straight tales, \frac{1}{4} tailless

6 0
3 years ago
Ellen has eggs she wishes to trade for grain. However, she cannot find anyone with grain that needs eggs. What is missing for th
77julia77 [94]
The correct answer is -

E. double coincidence of wants
4 0
3 years ago
6. A scientist measures the circumference of acorns in a population of oak trees
melisa1 [442]

Answer:

6. 2 cm

8. Greater than 2 cm and less than 2 cm

Explanation:

Complete Question

6. A scientist measures the circumference of acorns in a population of oak trees and discovers that the most common circumference is 2 cm. What would you expect the most common circumference(s) to be after 10 generations of stabilizing selection?

-2 cm

-Greater than 2 cm or less than 2 cm

-Greater than 2 cm and less than 2 cm

-Can't tell from the information given

8. Refer to question 6, but this time answer what you would expect after 10

generations of directional selection.

-2 cm

-Greater than 2 cm or less than 2 cm

-Greater than 2 cm and less than 2 cm

-Can't tell from the information given

Solution -

6. In an stabilizing selection, the average trait of a given population is favored over extreme values. Hence, it can be said that one specific trait is over presented in a given population. For example – uniform human birth weight, number of eggs a bird lay etc.  

Here in this case if most common circumference is 2 cm , then the tree population will try to have this trait as a stabilizing trait.  

Thus, option A is correct

8. In a  directional selection, the genetic variation decreases as per the environmental change. And hence the average trait will not be selected. Instead traits either higher or lower the average values will be preferred.  

Thus, option C is correct

3 0
3 years ago
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