Wavelength = 20 m = 0.20 m
frequency = 3*10^8 / 0.20 = 1.5 * 10^9 Hertz
Centripetal acceleration is the motion inwards towards the center of a circle. It is given by the square of velocity, divided by the radius of the circular path.
ac = v²/r, where ac is the centripetal acceleration in m/s²
Therefore,
Centripetal acceleration = 3²/20m
= 9/20m
= 0.45 m/s²
Thus, the centripetal acceleration is 0.45 m/s²
Explanation:
Mg-2+C+4>Mg2C.
Here you divide the four by the two and transfer the two toMg. In reactions like this oxidation numbers are exchanged.
Answer:
1.196 m
Explanation:
Given the wave equation :
y= 0.05 cos(5.25x-1775t)
Recall the general traverse wave relation :
y(x, t) = Acos(kx - wt)
A = Amplitude
To Obtian the wavelength ;
We compare the both equations :
Take the value of k ;
kx = 5.25x
k = 5.25
Recall;
k = 2π/λ
5.25 = 2π/λ
5.25λ = 2π
λ = 2π / 5.25
λ = (2 * 3.14) / 5.25 = 1.196 m
Answer:
the average force exerted by seatbelts on the passenger is 5625 N.
Explanation:
Given;
initial velocity of the car, u = 50 m/s
distance traveled by the car, s = 20 m
final velocity of the after coming to rest, v = 0
mass of the passenger, m = 90 kg
Determine the acceleration of the car as it hit the pile of dirt;
v² = u² + 2as
0 = 50² + (2 x 20)a
0 = 2500 + 40a
40a = -2500
a = -2500/40
a = -62.5 m/s²
The deceleration of the car is 62.5 m/s²
The force exerted on the passenger by the backward action of the car is calculated as follows;
F = ma
F = 90 x 62.5
F = 5625 N
Therefore, the average force exerted by seatbelts on the passenger is 5625 N.