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yulyashka [42]
4 years ago
11

A cat is moving at 18 m/s when it accelerates at 4 m/s2 for 2 seconds. what is his new velocity?

Physics
2 answers:
larisa [96]4 years ago
8 0
Velocity =18
Velocity at 2 seconds=18+4+4=26
shutvik [7]4 years ago
6 0

Answer:

26m/s

Explanation:

Acceleration is the change in velocity of a body with respect to time. Mathematically,

Acceleration = change in velocity/time

Acceleration = final velocity (v) - initial velocity (u)/time (t)

Given a = 4m/s², v = ? u = 18m/s, t = 2seconds.

Substituting in the given formula,

4 = v-18/2

8 = v-18

v = 8+18

v = 26m/s

The new velocity of the body is therefore 26m/s

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5 0
3 years ago
ASAP pls answer right and I will mark brainiest
Ronch [10]
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6 0
3 years ago
Can someone please help!!
frosja888 [35]

Answer:

Weight needed to balance the bar is 8.5N

Explanation:

Given the weight of the bar is 8N

The length of the bar is 5m

The weight of the bar will be uniformly distributed over the entire span. We will consider this as a point load acting in the middle of span length, which is at a distance of 2.5m from both ends.

Now applying momentum equation about balanced load we get, (see attachment)

\sum m_i=0\\2(m)+8(1)-8(0.5)-7(3)=0\\2m+8-4-21=0\\2m-17=0\\2m=17\\m=\frac{17}{2}=8.5\\So,\ m=8.5N

7 0
3 years ago
I need to find the current resistance and voltage for each in this complicated circuit plz help
konstantin123 [22]

Explanation:

The 11Ω, 22Ω, and 33Ω resistors are in parallel.  That combination is in series with the 4Ω and 10Ω resistors.

The net resistance is:

R = 4Ω + 10Ω + 1/(1/11Ω + 1/22Ω + 1/33Ω)

R = 20Ω

Using Ohm's law, we can find the current going through the 4Ω and 10Ω resistors:

V = IR

120 V = I (20Ω)

I = 6 A

So the voltage drops are:

V = (4Ω) (6A) = 24 V

V = (10Ω) (6A) = 60 V

That means the voltage drop across the 11Ω, 22Ω, and 33Ω resistors is:

V = 120 V − 24 V − 60 V

V = 36 V

So the currents are:

I = 36 V / 11 Ω = 3.27 A

I = 36 V / 22 Ω = 1.64 A

I = 36 V / 33 Ω = 1.09 A

If we wanted to, we could also show this using Kirchhoff's laws.

7 0
3 years ago
Calculate the amount of work for a car that exerts 10N and travels a distance of 5 meters.
lesya [120]

Answer:

50 j

Explanation:

W=Force*distance

W=10N*5M

W=50 NM

n*m = joules so you can say 50joules

4 0
3 years ago
Read 2 more answers
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