2 years ago

-15 (miles) + 15 (per hour)?

Physics

1 answer:

larisa86 [58]2 years ago

4 0

Answer:

Explanation:

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An α-particle has a charge of +2e and a mass of 6.64 10-27 kg. It is accelerated from rest through a potential difference that h

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$v_2=1.09\times 10^7\ m/s$

Explanation:

It is given that,

Charge of alpha particle, $q=2e=2\times 1.6\times 10^{-19}=3.2\times 10^{-19}\ C$

Mass of the alpha particle, $m=6.64\times 10^{-27}\ kg$

Potential difference, $(V_1-V_2)=1.24\times 10^6\ V$

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The α-particle moves perpendicular to the magnetic field at all times. The initial speed of the alpha particle is 0 as it is at rest. Using the conservation of energy as :

$\dfrac{1}{2}mv_1^2+qV_1=\dfrac{1}{2}mv_2^2+qV_2$

$v_2$ is the speed of the α–particle

$q(V_1-V_2)=\dfrac{1}{2}mv_2^2$

$v_2=\sqrt{\dfrac{2q(V_1-V_2)}{m}}$

$v_2=\sqrt{\dfrac{2\times 3.2\times 10^{-19}\times 1.24\times 10^6}{6.64\times 10^{-27}}}$

$v_2=1.09\times 10^7\ m/s$

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Maximum speed of the car is 26.56 m/s.

Explanation:

Given that,

Mass of the car, m = 1200 kg

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We need to find the maximum speed of the car. On the circular curve, the centripetal force is balanced by the force of friction. So,

$\dfrac{v^2}{r}=\mu g\\\\v=\sqrt{\mu gr} \\\\v=\sqrt{0.8\times 9.8\times 90} \\\\v=26.56\ m/s$

So, the maximum speed of the car is 26.56 m/s.

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