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mars1129 [50]
2 years ago
15

-15 (miles) + 15 (per hour)?

Physics
1 answer:
larisa86 [58]2 years ago
4 0

Answer:

<h2>15 ball in your face per hour </h2>

Explanation:

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A potential energy function is given by U(x)=(3.00J)x+(1.00J/m2)x3. What is the force function F(x) (in newtons) that is associa
Anit [1.1K]

Answer:

F(x)=-3 N - (3N)x^2

Explanation:

The force is defined as the negative of the derivative of the potential energy:

F=-\frac{dU}{dx}

If we use the potential energy function given in this problem:

U(x)=3.00 x + 1.00 x^3

and we calculate the force, we get:

F(x)=-\frac{d}{dx}(3x+x^3)=-3-3x^2

So, the force is

F(x)=-3 N - (3N)x^2

5 0
2 years ago
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When do two different position-time graphs have<br> matching velocity-time graphs?
Ivan

Answer:

when they have the same slope

8 0
3 years ago
Explanation for question i &amp; ii. Thank you.
suter [353]
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6 0
2 years ago
A ball is dropped off the balcony of a hotel room and it takes 2.8s to fall to the ground . how high above the ground is the bal
RideAnS [48]

The height of the ball above the ground is 38.45 m

First we will calculate the velocity of the ball when it touch the ground by using first equation of motion

v=u+gt

v=0+9.81×2.8

v=27.468 m/s

now the height of the ground can be calculated by the formula

v=√2gh

27.468=√2×9.81×h

h=38.45 m

5 0
2 years ago
2 objects have a total momentum of 400kg m/s, they collide. Object A’s mass is5kg &amp; object B’s mass is 11kg. After the colli
ss7ja [257]

Answer:

Explanation:

We shall apply law of conservation of momentum .

Momentum before collision = momentum after collision .

Momentum before collision = 400 kg m/s

Momentum after collision = 5  x v + 11 x 15

where v is velocity of A after the collision .

5  x v + 11 x 15 = 400

5 v = 400 - 165

5v = 235

v = 47 m /s .

3 0
3 years ago
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