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3 years ago

HELPPPPPPPPPPPPPPPPPPPPPPPPP MEEEEEEEEEEE NO ONE IS HELPING

Mathematics

1 answer:

hichkok12 [17]3 years ago

5 0

Step-by-step explanation:

1. Using the limit definition of derivative, find the derivative function,

= −2x + 2.

dont trust my answer dubble check i never trust myself i dont want you to get it wrong

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The graph of the piecewise function f(x) is shown what is the domain of f(x)

Rom4ik [11]

The domain of a function is where we have a value for x.

Since that's the case the domain of f(x) = {x e R / 1 ≤ x < 5}

We see that we have a value for x = 1 cuz we have a filled circle, but we don't have a value for x = 5, look at the unfilled circle

So, our x can vary between 1 and 5, but can't be 5.

8 0

3 years ago

5) Solve: 2.4p + 6 = 48

KatRina [158]

Answer:

p = 17.5

Step-by-step explanation:

This is the answer because:

1) First, we have to isolate x

2) To isolate x, first -6 from +6 and 48

+6 - 6 = 0

48 - 6 = 42

Equation: 2.4p = 42

3) Now we are left with 2.4p = 42

4) Next, divide 2.4 from 2.4 and 42

2.4/2.4 = 0

42/2.4 = 17.5

5) We are left with

p = 17.5

Therefore, the answer is p = 17.5

Hope this helps!

3 0

3 years ago

Simplify the given expression. Assume that no variable equal 0.

marissa [1.9K]

Answer:

The answer I think is correct is B

Step-by-step explanation:

I hope that's corrected?

5 0

3 years ago

Suppose that we don't have a formula for g(x) but we know that g(3) = −5 and g'(x) = x2 + 7 for all x.

Leni [432]

Answer:

$g(2.9) \approx -6.6$

$g(3.1) \approx -3.4$

The values are too small since $g''$ is positive for both values of $x$ in. I'm speaking of the $x$ values, 2.9 and 3.1.

Step-by-step explanation:

The point-slope of a line is:

$y-y_1=m(x-x_1)$

where $m$ is the slope and $(x_1,y_1)$ is a point on that line.

We want to find the equation of the tangent line of the curve $g$ at the point $(3,-5)$ on $g$ .

So we know $(x_1,y_1)=(3,-5)$ .

To find $m$ , we must calculate the derivative of $g$ at $x=3$ :

$m=g'(3)=(3)^2+7=9+7=16$ .

So the equation of the tangent line to curve $g$ at $(3,-5)$ is:

$y-(-5)=16(x-3)$ .

I'm going to solve this for $y$ .

$y-(-5)=16(x-3)$

$y+5=16(x-3)$

Subtract 5 on both sides:

$y=16(x-3)-5$

What this means is for values $x$ near $x=3$ is that:

$g(x) \approx 16(x-3)-5$ .

Let's evaluate this approximation function for $g(2.9)$ .

$g(2.9) \approx 16(2.9-3)-5$

$g(2.9) \approx 16(-.1)-5$

$g(2.9) \approx -1.6-5$

$g(2.9) \approx -6.6$

Let's evaluate this approximation function for $g(3.1)$ .

$g(3.1) \approx 16(3.1-3)-5$

$g(3.1) \approx 16(.1)-5$

$g(3.1) \approx 1.6-5$

$g(3.1) \approx -3.4$

b) To determine if these are over approximations or under approximations I will require the second derivative.

If $g''$ is positive, then it leads to underestimation (since the curve is concave up at that number).

If $g''$ is negative, then it leads to overestimation (since the curve is concave down at that number).

$g'(x)=x^2+7$

$g''(x)=2x+0$

$g''(x)=2x$

$2x$ is positive for $x>0$ .

$2x$ is negative for $x$ .

That is, $g''(2.9)>0 \text{ and } g''(3.1)>0$ .

So $2x$ is positive for both values of $x$ which means that the values we found in part (a) are underestimations.

6 0

4 years ago

Help please ASAP!!!!

Semenov [28]

The answer would be 65.9%. Add both paper numbers together (26.5+51.3) which is to 77.8.. to find paper not recycled just put 51.3/77.8 which would be 0.659 as a decimal.. move the decimal over to the right twice and that'd be your percentage.

8 0

4 years ago