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Rashid [163]
3 years ago
15

What is the difference between the mean and median (rounded to the nearest tenth) of these numbers 6,6,6,7,7,7,8,8,8,9

Mathematics
1 answer:
Nadusha1986 [10]3 years ago
3 0

The median is the moddle number of a data set. If the number of numbers is even add the 2 middle numbers and divide by 2.

Median = (7+7)÷2 = 7

The mean is the averagw value in a data set. You find it be adding all the numbers and then divide the answer by the number of numbers.

Mean: (6+6+6+7+7+7+8+8+8+9) ÷ 10

= 72 ÷ 10 = 7.2

Happy to help! Marking my answer as the Brainliest would really be aprreciated.

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3 years ago
Graph the polygon and its image after a dilation centered at C(1,1)
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Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The <em>original</em> polygon is highlighted in <em>red</em> and the image is highlighted in <em>blue</em>.

DIlations are defined by the follwing operation:

P'(x,y) = O(x,y) + k\cdot [P(x,y)-O(x,y)] (1)

Where:

  • O(x,y) - Center of dilation.
  • k - Dilation factor.
  • P(x,y) - Original point of the polygon.
  • P'(x,y) - Dilated point of the polygon.

If we know that O(x,y) = (1,1), k = 0.5, J(x,y) = (3,1), K(x,y) = (5, -3), L(x,y) = (5,5) and M(x,y) = (3,7), then the coordinates of the new polygon are:

J'(x,y) = (1,1) + 0.5\cdot [(3,1)-(1,1)]

J'(x,y) = (1,1)+0.5\cdot (2,0)

J'(x,y) = (1,1) +(1,0)

J'(x,y) = (2,1)

K'(x,y) = (1,1) + 0.5\cdot [(5,-3)-(1,1)]

K'(x,y) = (1,1) +0.5\cdot (4,-4)

K'(x,y) = (1,1) +(2,-2)

K'(x,y) = (3,-1)

L'(x,y) = (1,1) + 0.5\cdot [(5,5)-(1,1)]

L'(x,y) = (1,1) + 0.5\cdot (4,4)

L'(x,y) = (1,1) + (2,2)

L'(x,y) = (3,3)

M'(x,y) = (1,1) + 0.5\cdot [(3,7)-(1,1)]

M'(x,y) = (1,1) +0.5\cdot (2,6)

M'(x,y) = (1,1) +(1,3)

M'(x,y) = (2,4)

Now we proceed to present the graphs of the polygon and its image with the help of a graphing tool. The <em>original</em> polygon is highlighted in <em>red</em> and the image is highlighted in <em>blue</em>.

We kindly invite to check this question on dilations: brainly.com/question/13176891

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