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tangare [24]
3 years ago
9

On a coordinate plane, an exponential function approaches y = 0 in quadrant 2. It increases into quadrant 1 and goes through (1,

2) and (2, 8). Which functions could represent a reflection over the y-axis of the given function? Check all that apply. g(x) = –One-half(4)x g(x) = 0.5(4)–x g(x) = 2(4)x g(x) = One-half (one-fourth)x g(x) = One-half (one-fourth)–x
Mathematics
2 answers:
tiny-mole [99]3 years ago
9 0

Answer:

a) g(x) = 0.5(4)–x

d) g(x) = One-half (one-fourth)x

maksim [4K]3 years ago
5 0

Answer:

B - g(x) = 0.5(4)–x

D - g(x) = One-half (one-fourth)x

Step-by-step explanation:

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Use the fraction model to multiply: three multiplied by three fifths. Leave your answer as an improper fraction.
Katena32 [7]

Answer:

it is six fifths your welcome

Step-by-step explanation:

8 0
2 years ago
Write an equation of the line that passes through (-4, -1) and is perpendicular to the line y= 4/3x+6.
scoundrel [369]

Answer:

y = (-3/4)x - 4

Step-by-step explanation:

The slopes of perpendicular lines are opposite reciprocals of each other. In other words, if the slope of one line is a/b, then the slope of the line perpendicular to it would be -b/a.

Here, the given slope is 4/3, so the slope of the perpendicular line is -3/4.

We are given a point (-4, -1) and we know the slope, so we can find the point-slope form of the line. Point-slope form is written as y - y1 = m(x - x1), where (x1,y1) is the point and m is the slope. Here, x1 = -4 and y1 = -1 and m = -3/4. So:

y - y1 = m(x - x1)

y - (-1) = (-3/4) * (x - (-4)) = (-3/4) * (x + 4)

y + 1 = (-3/4)x + (-3/4) * 4 = (-3/4)x - 3

y = (-3/4)x - 3 - 1

y = (-3/4)x - 4

3 0
2 years ago
Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ
tensa zangetsu [6.8K]

Answer:

y=3t^9+C

Step-by-step explanation:

Given:  \dfrac{dy}{dt}=27t^8

We want to obtain the general solution of the given differential equation.

dy=27t^8$ dt\\$Take the integral of both sides\\\int dy =\int 27t^8$ dt$\\y=\dfrac{27t^{8+1}}{8+1} +C$, (where C is the constant of integration)$\\y=\dfrac{27t^{9}}{9} +C\\\\y=3t^9+C

The general solution of the differential equation is: y=3t^9+C

CHECK:

\dfrac{d}{dt} y=\dfrac{d}{dt}(3t^9+C)=\dfrac{d}{dt}(3t^9)+\dfrac{d}{dt}(C)\\\\\text{Since derivative of a constant is zero}\\\\\dfrac{dy}{dt}=27t^{9-1}\\\dfrac{dy}{dt}=27t^8

4 0
3 years ago
What is the value of x in 7x-2+x+x
ratelena [41]
Hello,

Work:

Equation;

7x - 2 + x + x

Collect like terms.

9x - 2 \: \: \: \: \: \: \: result

Hope this helps.
r3t40
4 0
2 years ago
(0,6) (-4,-9)
Olegator [25]

Answer:

d=√(16+225)

d=√241

d=15.5

I would appreciate if my answer is chosen as a brainliest answer

6 0
2 years ago
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