Answer:
c. (12.12, 18.48)
Step-by-step explanation:
Hello!
The study variable is X: number of times a racehorse is raced during its career.
The average number is X[bar]= 15.3 and the standard deviation is S= 6.8 obtained from a sample of n=20 horses.
To estimate the population mean you need that the variable has a normal distribution, in this case, we have no information about its distribution so I'll assume that it has a normal distribution. With n=20 the most accurate statistic to use for the estimation is a Students-t for one sample, the formula for the interval is:
X[bar] ± 

[15.3 ± 2.093 *
]
[12.12; 18.48]
Using a significance level of 95% you'd expect that the true average of times racehorses are raced during their career is included in the interval [12.12; 18.48].
I hope it helps!
Answer with Step-by-step explanation:
We are given that
Total dogs=24
Total cats=18
Total animals=24+18=42
Male dogs=8
Male cats=6
Total male animals=8+6=14
Total female animals=42-14=28
Female cats=18-6=12
Dogs female=24-8=16
a.We have to find the probability that the pet is male, given that it is cat.
It means we have to find P(Male/cat)
Conditional probability: 
P(Cat)=


P(male/cat)=
b.


c.P(Dog)=



L=25
If the length is 25 yards then you use 50 yards of fencing for the length, this leaves ten yards for each width of fencing each.
10 yards is 15 yards less than 25 yards showing that this is the correct answer.