Answer:
12
Step-by-step explanation:
For this question, simply plug in -2 for x:
Hope this helps!!
Find x on this problem
1 answer:
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Answer:
117.5 ft²
Step-by-step explanation:
To find the area of the shaded area, we can find the area of the square, then subtract the areas of the two semicircles.
First, we will find the area of the given square, by using the formula , multiplying the length and width. The dimensions of this square are 14×14.
14 · 14 = 196
The area of the square is 196 ft².
We can now find the area of the two congruent half-circles. Since they are identical, we can simply find the area of one circle if it was whole. To find the area of a circle, we'll use the formula . With some simple deduction, we can see that the diameter of the circle is 10 ft, so the radius would be 5 ft long. Plug our values into the formula.
A = 5²
We will use 3.14 for .
A = 78.5
The area of both the semicircles is 78.5 ft².
Now, we can subtract.
196 - 78.5 = 117.5
The area of the figure is 117.5 ft².
Good luck ^^
The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.
<h3>What is the end behavior about?</h3>The end behavior of a function f tells us that the way that the graph function behaves at the "ends" of the x-axis.
Note that the end behavior of a function tells the trend of the graph and in this graph, f(x) -----> +∞ as x----> -∞ (as the value of x decreases the value of f(x) increases) and f(x) -----> -∞ as x----> +∞ (as the value of x increases the value of f(x) decreases).
Therefore, The end behavior of the graph of f(x) = -0.25x2 - 2x + 1 is that A) As x increases, f(x) increases. As x decreases, f(x) decreases.
See full question below
What is the end behavior of the graph of f(x) = -0.25x2 - 2x + 1?
A) As x increases, f(x) increases. As x decreases, f(x) decreases.
B) As x increases, f(x) decreases. As x decreases, f(x) decreases.
C) As x increases, f(x) increases. As x decreases, f(x) increases.
D) As x increases, f(x) decreases. As x decreases, f(x) increases
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