The correct answer is: [A]: " <span>x - 3 " .
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Answer:
Question 1: DE is congruent to GH
Question 2: angle-side-side
Question 3: 153
Question 4: the first choice
Question 5: 26
Step-by-step explanation:
Step-by-step explanation:
Note: Question does not indicate if probability required is for weight to exceed or below 3000 lbs. So choose appropriate answer accordingly (near the end)
Using the usual notations and formulas,
mean, mu = 3550
standard deviation, sigma = 870
Observed value, X = 3000
We calculate
Z = (X-mu)/sigma = (3000-3550)/870 = -0.6321839
Probability of weight below 3000 lbs
= P(X<3000) = P(z<Z) = P(z<-0.6321839) = 0.2636334
Answer:
Probability that a car randomly selected is less than 3000
= P(X<3000) = 0.2636 (to 4 decimals)
Probability that a car randomly selected is greater than 3000
= 1 - P(X<3000) = 1 - 0.2636 (to 4 decimals) = 0.7364 (to 4 decimals)
Answer:
The new height requirements are minimum of 64.1875 inches and maximum of 68.3 inches
Step-by-step explanation:
To exclude the tallest 50% of men and shortest 5% of men, we need to find the critical z-value for a significance level of 0.5 & 0.05 and then solve for x in the z-score equation.
For significance value of 0.5, z = 0
We are given;
μ = 68.3 in
σ = 2.5 in
Thus from z = (x - μ)/σ, we have;
0 =(x - 68. 3)/2.5
0 = x - 68. 3
x = 68.3 inches for men max
Similarly, for significance value of 0.05, z = -1.645
Thus to find x;
-1.645 = (x - 68. 3)/2.5
-4.1125 = x - 68.3
x = 68.3 - 4.1125
x = 64.1875 inches for men min
