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3 years ago

HEy, CAn YOu HElp ? :) Plssss (picture below) solve for #5

Mathematics

1 answer:

alexira [117]3 years ago

4 0

Answer: a=60°, b=25°, c=95°,d=60°, e=25°, f=95°, g=60, h=35°

Step-by-step explanation:

a=60°, Because the angle opposite to it is 60°

b=25°, Because if you take 180°-155°, you get 25°

c=95°, Because if you add angles a and b, you get 85°, then you do 180°-85°=95°

d=60°, Because the angle opposite to it does

f=95°, Because angle c, which is opposite to it equals 95°

g=60°, Because if you add angles e and f, you get 85°, then you take 180°-85=95°

h=35°, Because if you add angles c and d, which is 155°, you take 180°-155=35°

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How do I solve this equation by completing the square. 4X^2 + 12x +5 = 21

Artyom0805 [142]

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3 years ago

a computer store bought a program at a cost of $10 and sold it at a selling price of $14. Find the percent markup.

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3 years ago

Read 2 more answers

I need help ASAP help me answer questions and then I put a picture up

olya-2409 [2.1K]

Answer:

(-4,9)

Step-by-step explanation:

To solve the system of equations, you want to be able to cancel out one of the variables. In this case, it'd be easiest to cancel out the x variables. To do this, you'll want to multiply everything in the first equation by 2 (2(x-5y=-49)=2x-10y=-98). Then, you can add the two equations together. 2x and -2x will cancel out, so you'll be left with -11y=-99. Next, solve for x by dividing both sides of the equation by -11, which will give you y=9. This is your y-coordinate! At this point, you're halfway to the answer as you just need your x-coordinate. It's not too difficult to find the x-coordinate, since you just substitute 9 into one of the equations. It doesn't matter which one you choose as you should get the same answer with both. I usually substitute the y-value into both equations, though, just to make sure I'm correct. Once you put the y-value into the equations, you should get x=-4 after solving it. :)

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2 years ago

which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9

elena55 [62]

Step-by-step explanation:

$\frac{(x - 2) {}^{2} }{4} + \frac{(y + 5) {}^{2} }{9} = 1$

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

${c}^{2} = {a}^{2} - {b}^{2}$

Here a^2 is 9, b^2 is 4.

${c}^{2} = 9 - 4$

${c}^{2} = 5$

$c = \sqrt{5}$

So our foci is

$(2, - 5 + \sqrt{5} )$

and

$(2, - 5 - \sqrt{5} )$

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1 year ago

What is the end behavior in the function y=2x^3-x

sasho [114]

Answer:

Step-by-step explanation:

When a question asks for the "end behavior" of a function, they just want to know what happens if you trace the direction the function heads in for super low and super high values of x. In other words, they want to know what the graph is looking like as x heads for both positive and negative infinity. This might be sort of hard to visualize, so if you have a graphing utility, use it to double check yourself, but even without a graph, we can answer this question. For any function involving x^3, we know that the "parent graph" looks like the attached image. This is the "basic" look of any x^3 function; however, certain things can change the end behavior. You'll notice that in the attached graph, as x gets really really small, the function goes to negative infinity. As x gets very very big, the function goes to positive infinity.

Now, taking a look at your function, 2x^3 - x, things might change a little. Some things that change the end behavior of a graph include a negative coefficient for x^3, such as -x^3 or -5x^3. This would flip the graph over the y-axis, which would make the end behavior "swap", basically. Your function doesn't have a negative coefficient in front of x^3, so we're okay on that front, and it turns out your function has the same end behavior as the parent function, since no kind of reflection is occurring. I attached the graph of your function as well so you can see it, but what this means is that as x approaches infinity, or as x gets very big, your function also goes to infinity, and as x approaches negative infinity, or as x gets very small, your function goes to negative infinity.

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2 years ago