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poizon [28]
2 years ago
6

How many non-square numbers lie between the 215to the power of 2 and 216 to the power of 2

Mathematics
1 answer:
Vaselesa [24]2 years ago
7 0

There are 430 non square numbers that lie between 215^{2} and 216^{2}.

Given two numbers 215^{2} and 216^{2} and we are require to find non square numbers that lie between them.

Numbers can be consecutive numbers or non consecutive numbers. In our question we will find the consecutive numbers.

Square numbers are those numbers whos square is in a proper number means decimal should not be there.

First number=215^{2}

Second number=216^{2}

First we have to find the exact value of numbers by finding the square of these numbers.

First number=215*215=46225

Second number=216*216=46656

Numbers that  lie between them=(46656-46225)-1

=431-1

=430

Hence 430 numbers lie between 215^{2} and 216^{2}.

Learn more about product at brainly.com/question/10873737

#SPJ4

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Which graph shows a line with the same y intercept as the graph of 10x - 16y = 40
Amanda [17]

Answer:

The graph option where the y-axis is intercepted at y = -2.5 by the line of the graph.

Step-by-step explanation:

The answer choices for the possible graphs that have the same y-intercept as the graph of 10x - 16y = 40 is missing here.

However, the answer can still be explained here.

We can figure out how the graph would look like.

First, understand that the y-intercept of a graph is the value of y, of the point where the line intercepts the y-axis.

Let's figure out what the y-intercept is given a graph represented by the equation, 10x - 16y = 40.

Rewrite the equation in slope-intercept form.

10x - 16y = 40

-16y = -10x + 40

y = -10x/-16 + 40/-16

y = ⅝x - ⁵/2

Therefore, the y-intercept of the graph of 10x - 16y = 40 is -⁵/2 or -2.5.

✅The graph shows a line with the same y-intercept as the graph of 10x - 16y = 40, would have it's y-axis intercepted at y = -2.5.

4 0
3 years ago
A 0.311 kg tennis racket moving 30.3 m/s east makes an elastic collision with a 0.0570 kg ball moving 19.2 m/s west. Find the ve
max2010maxim [7]

<u>Answer</u>:

The velocity of the tennis racket after the collision 14.966 m/s.

<u>Step-by-step explanation:</u>

An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.

So, the total kinetic energy before collision = the total kinetic energy after collision.

For the given problem let the following:

m₁ = mass of tennis racket = 0.311 kg

m₂ = mass of the ball = 0.057 kg

u₁ = velocity of tennis racket before collision = 30.3 m/s

u₂ = velocity of the ball before collision = -19.2 m/s

v₁ = velocity of tennis racket after collision

v₂ = velocity of the ball after collision

Right ⇒east  (+) , Left⇒ west (-)

v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)

  = ( 30.3 * (0.311 - 0.057) - 19.2 * 2 * 0.057 ) / ( 0.311 + 0.057)

  = 14.966 m/s.

So, the velocity of the tennis racket after the collision 14.966 m/s.

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