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GarryVolchara [31]

3 years ago

14

Help me please What’s the slope of the line passing through (-2, -8)and (-3,-9)

1 answer:

Alexandra [31]3 years ago

7 0

Answer:

Positive one

Step-by-step explanation:

You might be interested in

Rewrite the equation to isolate the variable.. df= g- 10 for d

ehidna [41]

Df = g - 10

To solve for d, divide both sides by f.

df / f = (g - 10) / f

d = (g - 10) / f

I hope this explains it.

6 0

4 years ago

Can u guys please help me!!

Alona [7]

Answer and Step-by-step explanation:

This problem requires the use of trigonometric functions, specifically the tangent trig function.

$tan(Angle)=\frac{opposite}{adjacent}$

Plug in the values.

$tan(40) = \frac{8000}{x}$

Multiply by x to both sides, then divide by tan(40) to both sides.

$x = \frac{8000}{tan(40)}$

Now, plug this into a calculator and rounded to the nearest whole number (foot).

x = 9534.0287

x = 9534 ft.

The answer is 9534 ft., the last option.

#teamtrees #WAP (Water And Plant)

5 0

3 years ago

De una carrera x km ya se han recorrido y km cuanto falta para terminar?

lisov135 [29]

Partari teneria roberta seneios para han recordiiooo sii

7 0

4 years ago

in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

8 0

3 years ago

A dentist office gives a survey to all wisdom teeth extraction patients asking them to rate the quality of their dental experien

Svetradugi [14.3K]

The correct answer is B. Most patients who have a poor dental experience also have post-extraction complications. This can be shown through the fact that of everyone who had a poor dental experience, 94% said they had post-extraction complication. 94% is obviously <em>most</em>. We can not confidently say that poor dental experiences cause post-extraction problems because we do not know how many people who had a normal or good experience also had problems.

3 0

3 years ago

Read 2 more answers