3 years ago

Simplify: first picture

Mathematics

1 answer:

nikdorinn [45]3 years ago

4 0

$\sqrt{8} +\sqrt{98}- \sqrt{64}$

Answer:

√8+√98−√64

=−8+9√2(Decimal: 4.727922)

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Line 1 passes through the points (-4, -6) and (12,2). line 2 passes through the points (-6,-2) and (-2,0). Do the lines intersec

kifflom [539]

The lines dont intersect

7 0

3 years ago

Three more than a number is 15

podryga [215]

Answer:

The number is 12

Step-by-step explanation:

If 15 is three more than the number is three less so you do, 15 - 3 which is 12.

I hope this helps

7 0

2 years ago

Simplify (-2x^4y^-3)^4

elixir [45]

Answer:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = \frac{16 {x}^{16}}{ {y}^{12} }$

Step-by-step explanation:

We want to simplify:

$( - 2 {x}^{4} {y}^{ - 3} )^{4}$

We need to apply the exponential property for products of powers.

Recall that:

$( {a}^{m} \times {a}^{n} )^{p} = {a}^{mp} \times {a}^{np}$

We apply this rule to get:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = ( { - 2)}^{4} x \times {x}^{16} \times {y}^{ - 12}$

This simplifies to:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = 16 {x}^{16} \times {y}^{ - 12}$

We rewrite as positive index to get:

$( - 2 {x}^{4} {y}^{ - 3} )^{4} = \frac{16 {x}^{16}}{ {y}^{12} }$

7 0

3 years ago

Q3. In a hydraulic lift, a 1400 N force is applied to a 0.5 m2 piston. Calculate the minimum surface area of the large piston to

blondinia [14]

Answer:

1.8m^2 approx

Step-by-step explanation:

Given data

P1= 1400N

A1=0.5m^2

P2=5000 N

A2=??

Let us apply the formula to calculate the Area A2

P1/A1= P2/A2

substitute

1400/0.5= 5000/A2

cross multiply

1400*A2= 5000*0.5

1400*A2= 2500

A2= 2500/1400

A2= 1.78

Hence the Area is 1.8m^2 approx

3 0

3 years ago

Twice a number take away one

OlgaM077 [116]

2x -1 is the answer I believe

8 0

3 years ago