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marusya05 [52]
2 years ago
14

Neal purchases a digital camera for his

Mathematics
1 answer:
Alika [10]2 years ago
7 0

Answer:

101.91

Step-by-step explanation:

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Solving the equation and something to do with log
Anastaziya [24]

Answer:

m= 1/2.

Step-by-step explanation:

To solve this, we must make the bases equivalent. We can do this by finding the common base which is 5.

We know that 125= 5³ and 25=5², which will help us in this equation. We can rewrite the equation substituting this for the original numbers:

5^{3(2m)} = 5^{2(m+1)} Distribute the exponents to get:

5^{6m} = 5^{2m+2}

Now, we can simply ignore the '5' and solve for 'm':

6m= 2m+2

4m= 2

m= 1/2.

3 0
3 years ago
Ervin sells vintage cars. Every three months, he manages to sell 13 cars. Assuming he sells cars at a constant rate, what is the
Minchanka [31]
The slope would be 4.33. He sells 13 cars in 3 months, 13/3=4.33 cars each month. While you can't sell 4.33, remember that this is just the slope. The equation would be apprx y=4.33(x)
3 0
3 years ago
Read 2 more answers
This is my hw somebody please
jek_recluse [69]

Answer:

4 because the edges are like vertices.

6 0
2 years ago
How many minutes are there in 2 3/5 hours
mars1129 [50]

156 minutes.

To find this, remember that an hour has sixty minutes. With this information, it is also given that there are two hours, thus meaning that we have to multiply sixty by two. This will give you 120. Next, you need to figure out the 3/5's portion of an hour. To find 1/5 of an hour, simply divide sixty by five. With that, you get the answer of 12. But because it says 3/5, you need to multiply 12 by 3, giving you 36. Finally, you add 36 to 120 to get the final answer of 156.

Hope this helps!

5 0
2 years ago
1+Sin/Cos + Cos/1+Sin = 2Sec
Bond [772]

Step-by-step explanation:

Consider the left-hand side:

\dfrac{1+\sin{\theta}}{\cos{\theta}} + \dfrac{\cos{\theta}}{1+\sin{\theta}}

\:\:\:\:= \dfrac{(1+\sin{\theta})^2 + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:=\dfrac{1+2\sin{\theta}+\sin^2{\theta} + \cos^2{\theta}}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:=\dfrac{2+2\sin{\theta}}{\cos{\theta}(1+\sin{\theta})} =\dfrac{2(1+\sin{\theta})}{\cos{\theta}(1+\sin{\theta})}

\:\:\:\:= \dfrac{2}{\cos{\theta}} = 2\sec{\theta}

7 0
2 years ago
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