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natka813 [3]
2 years ago
9

C) 2×x×3×yim just typing now bc it says i need 20 characters but yh ​

Mathematics
2 answers:
Scorpion4ik [409]2 years ago
6 0

Answer:

the answer is 6xy , hopefully that helped you

Alla [95]2 years ago
4 0

Answer:

2x^9 x

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x3"   was replaced by   "x^3".  

STEP  1 :

Multiplying exponential expressions :

1.1    x4 multiplied by x3 = x(4 + 3) = x7

The Equation at the end of step  1 :

 ((2x7 • x) • x) • y

STEP  2:  Final result :

 2x^9 y

Hope this helps!

Brain-List?

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3(x-4) - (x+5) = 2x-11
dimaraw [331]
The answer is 6
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3 0
3 years ago
Given the following roots build a polynomial function in standard form: -3 and +2
swat32

Answer:

  f(x) = x² +x -6

Step-by-step explanation:

The standard form will look like ...

  f(x) = x² +bx +c

where b is the opposite of the sum of the roots, and c is their product.

  f(x) = x² -(-3+2)x +(-3)(2)

  f(x) = x² +x -6

_____

<em>Additional comment</em>

In general, "standard form" is ax²+bx+c. In this case, the coefficient 'a' can be 1 since neither of the roots is expressed as a fraction. The sum of roots is (-b/a) and the product of roots is (c/a).

3 0
2 years ago
Consider a circle whose size can vary. Let r r represent the radius of the circle (in cm) and let C C represent the circumferenc
Ket [755]

Answer:

  f(r) = 2πr

Step-by-step explanation:

You know the formula for circumference in terms of radius is ...

  C = 2πr

You are being asked to write this as a function named "f". That will be ...

  f(r) = 2πr

8 0
3 years ago
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The grid below shows figure Q and its image figure Q' after a transformation:
Masteriza [31]
<h3>Answer: choice B) counterclockwise rotation of 90 degrees around the origin</h3>

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4 0
3 years ago
What is the Volume of the square pyramid? (Round to the nearest tenth as needed)
goldenfox [79]

Answer:

5229 mm³

Step-by-step explanation:

Volume of square pyramid

\sf \boxed{Volume \ of \ the \ square \ pyramid = \dfrac{1}{3}*b^2*H}

      b = base length = 25 mm

       H = height

         We have to find 'H' using Pythagorean theorem,

              slant height (hypotenuse) = 28 mm

                                                  leg₁ = base length  ÷ 2 = 25÷2 = 12.5

                                                  leg₂ = H

     H² + (12.5)² = 28²

                  H²   = 784 - 156.25

                         = 627.75

                   \sf H = \sqrt{627.75}

                 H = 25.01 mm

          \sf  \text{Volume of square pyramid =$\dfrac{1}{3}*25*25*25.1$ }

                                                     = 5229 mm³

                                                     

       

\sf \boxed{\text{Volume of square pyramid = \dfrac{1}{3}*25*25*28}}

3 0
2 years ago
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