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natka813 [3]
2 years ago
9

C) 2×x×3×yim just typing now bc it says i need 20 characters but yh ​

Mathematics
2 answers:
Scorpion4ik [409]2 years ago
6 0

Answer:

the answer is 6xy , hopefully that helped you

Alla [95]2 years ago
4 0

Answer:

2x^9 x

Step-by-step explanation:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "x3"   was replaced by   "x^3".  

STEP  1 :

Multiplying exponential expressions :

1.1    x4 multiplied by x3 = x(4 + 3) = x7

The Equation at the end of step  1 :

 ((2x7 • x) • x) • y

STEP  2:  Final result :

 2x^9 y

Hope this helps!

Brain-List?

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Aaaaaaaaaaaaaaqqqqqqaaaaaaaaa help
Andrews [41]

Answer:

0.05?

Step-by-step explanation:

0.2 are taken by oarents

3/4 = 0.75 were taken by parents

0.20 + 0.75 = 0.95

1.00 - 0.95 = 0.05

7 0
3 years ago
Find the measure of the arc.<br><br> 146°E<br><br> mFD =
Verizon [17]

Answer:

arc FD = 236°

Step-by-step explanation:

The measure of the arc is equal to the measure of the central angle it subtends, thus

arc FD = arc FE + arc ED = 146° + 90° = 236°

4 0
3 years ago
James has $32 and earns $10 per week for his allowance. What is the initial value for the scenario described?
nignag [31]
32 is your initial value, because that is what he starts with

6 0
3 years ago
Read 2 more answers
Integrate <img src="https://tex.z-dn.net/?f=e%5E%7B4x%7D%5Csqrt%7B1%2Be%5E%7B2x%7D%20%7D%20dx" id="TexFormula1" title="e^{4x}\sq
AnnyKZ [126]

Answer:

(\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

Step-by-step explanation:

<u><em> Step(i):-</em></u>

Given that the function

                    f(x) = e^{4x} \sqrt{1+e^{2x} }

Now integrating on both sides, we get

                 \int\limits{f(x)} \, dx = \int\limits{e^{4x} \sqrt{1+e^{2x} } dx

                               =    \int\limits{e^{2x} e^{2x} \sqrt{1+e^{2x} } dx

                         

<u><em>Step(ii):-</em></u>

  Let  1 + e^{2x}  = t

           e^{2x}  = t -1  

          2e^{2x}dx = d t

          e^{2x}dx = \frac{1}{2} d t

                = \int\limits{( \sqrt{1+e^{2x} }) e^{2x} e^{2x} dx

                  = \int\limits {\sqrt{t}(t-1)\frac{1}{2} dt }

                 = \frac{1}{2} \int\limits {\sqrt{t} (t) -\sqrt{t} ) dt }

                = \frac{1}{2} \int\limits {(t^{\frac{1}{2}  } t^{1} +t^{\frac{1}{2} } ) } \, dx

                = \frac{1}{2} \int\limits {(t^{\frac{3}{2}  } +t^{\frac{1}{2} } ) } \, dx

               = \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{3}{2}+1 } + \frac{t^{\frac{1}{2} +1} }{\frac{1}{2}+1 } )+C

              =  \frac{1}{2} (\frac{t^{\frac{3}{2} +1} }{\frac{5}{2} } + \frac{t^{\frac{1}{2} +1} }{\frac{3}{2} } )+C

             = \frac{1}{2} (\frac{t^{\frac{5}{2} } }{\frac{5}{2} } + \frac{t^{\frac{3}{2} } }{\frac{3}{2} } )+C

            = (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

<u><em>Final answer:-</em></u>

= (\frac{(1+e^{2x}) ^{\frac{5}{2} } }{{5}} + \frac{(1+e^{2x} )^{\frac{3}{2} } }{{3}} )+C

             

3 0
3 years ago
(Blank) x 1/6 = 5/6<br><br><br> I haven’t done this in a while so I need help.
dexar [7]

Answer:

5

Step-by-step explanation:

Divide 5/6 by 1/6 to get 5 as your answer.

8 0
3 years ago
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