Answer: -2x - 10
Steps: -2(x+5)
Apply the distributive law [ a(b + c) = ab + ac ]:
a = -2, b = x, c = 5
-2x + (-2) × 5
Apply minus/plus rules: -2x - 2 × 5
Multiply the numbers: 2 × 5 = 10
-2x - 10
Plz mark brainliest:)
Answer:
128
Step-by-step explanation:
8 - 5 x 3 x -2^3
8 - 5 x 3 x -8
8 - 15 x -8
8 - -120
128
To factor quadratic equations of the form ax^2+bx+c=y, you must find two values, j and k, which satisfy two conditions.
jk=ac and j+k=b
The you replace the single linear term bx with jx and kx. Finally then you factor the first pair of terms and the second pair of terms. In this problem...
2k^2-5k-18=0
2k^2+4k-9k-18=0
2k(k+2)-9(k+2)=0
(2k-9)(k+2)=0
so k=-2 and 9/2
k=(-2, 4.5)
6 remainder 4 because if you do 8x6 you get 48 and if you subtract 48 from 52 you get remainder 4
