7:48 pm when converted into regular time.
Answer:
-19
Step-by-step explanation:
2×2-2z4+y2-x2+z4
now we put the value,
4-2(2to the power 4)+(3 to the power 2)-(-4 to the power 2)+(2 to the power 4)
4-2×16+9-16+16
4-32+9
4+9-32
13-32
-19
please check the answer again i am sorry if it's wrong
Answer:
y = 3x + 2
Step-by-step explanation:
The equation for two points on a line is generated from the straight line equation y = mx + b ---------------- eqn (i)
where m, the slope = (y2 - y1) / (x2 - x1)
therefore for (0,2) and (1,5) m = (5 - 2)/(1 - 0) = 3
This implies that eqn (i) can be rewritten as:
y = 3x + b ------------------- eqn (ii)
pickintg the point (0,2) and substituting into eqn (ii)
2 = 3(0) + b
this implies that b = 2
for confirmation with (1,5)
5 = 3(1) + b
b = 5 - 3 = 2
hence m = 3, b = 2
the equation is y = 3x + 2
Answer: 2 - 4x = 6
Please mark me as brainliest
Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
_____
The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.