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STatiana [176]
3 years ago
6

Simplify the expression 7y − (6)2y − 12

Mathematics
2 answers:
irina [24]3 years ago
6 0

Answer:

-5y-12

Step-by-step explanation:

Multiply 6 into 2y

7y-12y-12

-5y-12

svlad2 [7]3 years ago
6 0
He’s right the guy on top
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When simplified and written in standard form, which quadratic function is equivalent to the polynomial shown?
mars1129 [50]

Answer:

2c^2 - 2c - 3

Step-by-step explanation:

Next time, please share the answer choices.  Thank you.

Group together the 'c' terms in 2 + 7c – 4c2 – 3c + 4:

                                                     2  + 4c and -4c^2 + 4  Then we have:

-4c^2 + 4c + 6

We should reduce this by factoring -2 out of all three terms:

2c^2 - 2c - 3  This is the desired quadratic in standard form.

3 0
2 years ago
Parallel to y=−3/4x, through (4, -1)
kolbaska11 [484]

Answer:

y=-\frac{3}{4}x+2

Step-by-step explanation:

The slope-intercept form is given by y=mx+c, where m is the slope and c is the y-intercept.

Slope of given line= -\frac{3}{4}

Parallel lines have the same slope. Thus, the slope of the line would also be -\frac{3}{4}.

y=-\frac{3}{4}x +c

The value of c can be found by substituting a pair of coordinates.

When x= 4, y= -1,

-1=-\frac{3}{4} (4)+c

-1= -3 +c

<em>Add 3 to both sides:</em>

c= -1 +3

c= 2

Thus, the equation of the line is \bf{y=-\frac{3}{4}x+2.

Additional:

Do check out the following for a similar question on slope-intercept form!

  • brainly.com/question/25549430
7 0
2 years ago
Suppose you pick two cards from a deck of 52 playing cards. What is the probability that they are both queens?
photoshop1234 [79]

Answer:

0.45% probability that they are both queens.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes

The combinations formula is important in this problem:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

Desired outcomes

You want 2 queens. Four cards are queens. I am going to call then A,B,C,D. A and B is the same outcome as B and A. That is, the order is not important, so this is why we use the combinations formula.

The number of desired outcomes is a combinations of 2 cards from a set of 4(queens). So

D = C_{4,2} = \frac{4!}{2!(4-2)!} = 6

Total outcomes

Combinations of 2 from a set of 52(number of playing cards). So

T = C_{52,2} = \frac{52!}{2!(52-2)!} = 1326

What is the probability that they are both queens?

P = \frac{D}{T} = \frac{6}{1326} = 0.0045

0.45% probability that they are both queens.

4 0
3 years ago
Solve for x in the equation x2 - 4x-9= 29
max2010maxim [7]
Shhjujtitytjtutyrktjrjtjjtejhw rye
7 0
3 years ago
1500/semiannual period for 6 years at 2.5%/year compounded semiannually
kari74 [83]

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$1500\\ r=rate\to 2.5\%\to \frac{2.5}{100}\dotfill &0.025\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannual, thus twice} \end{array}\dotfill &2\\ t=years\dotfill &6 \end{cases} \\\\\\ A=1500\left(1+\frac{0.025}{2}\right)^{2\cdot 6}\implies A=1500(1.0125)^{12}\implies A\approx 1741.13

6 0
3 years ago
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