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matrenka [14]
3 years ago
15

Here is an equation 2x + 9 = -15. What are three different equations that have the same solution as that equation? Show or expla

in how you found them Please
Mathematics
1 answer:
Sliva [168]3 years ago
6 0

To find those equations we can do any multiplication or division of both sides of the equation:

Examples:

2x + 9 = -15              | · 2

4x + 18 = -30

2x + 9 = -15              | · (-1)

-2x - 9 = 15

2x + 9 = -15               | ÷ 2

x + 4.5 = -7.5

There is the same solution: x = -12.

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What is the correct answer to this multiple choice question? Please help!!!
dybincka [34]

Answer:

By translating the function cos(x) 90 degrees to the right.

Step-by-step explanation:

The sine function is just the cosine function translated 90 degrees to the right. You can see the visualization below. They overlap.

If you're wondering why the diagram shows a shift in

\pi / 2

That's just the equivalent to 90 degrees in radians.

8 0
3 years ago
PLEASE HELP ME SHOW ME HOW U GOT YOUR ANSWER PLZ AND THANK U
lara [203]

Answer:

2/3

Step-by-step explanation:

There are 6 marbles in the jar

4 are not purple

P(not purple) = marbles that are not purple/ total marbles

                      = 4/6 = 2/3

3 0
3 years ago
Read 2 more answers
In a class of 32 boys, 16 passed the
vodka [1.7K]

Answer:

3/8

Step-by-step explanation:

12/32 failled and if you simplify this it means that about 3/8 of the class failled

8 0
3 years ago
Read 2 more answers
What 2 numbers add to get 2 and multiply to 4
rusak2 [61]
Factor 4
4=1 times 4
2 times 2
they don't add to 2
set up equation
x+y=2
xy=4

first equation, subtract x from both sides
y=2-x
subsitute for y
x(2-x)=4
distribute
2x-x^2=4
add x^2
2x=x^2+4
subtract 2x
0=x^2-2x+4
use quadratic formula which is
if you have ax^2+bx+c=0 then
x=\frac{ -b+/-\sqrt{b^{2}-4ac} }{2a} so

1x^2-2x+4=0
a=1
b=-2
c=4
x=\frac{ -(-2)+/-\sqrt{(-2)^{2}-4(1)(4)} }{2(1)}
x=\frac{ 2+/-\sqrt{4-16} }{2}
x=\frac{ 2+/-\sqrt{-12} }{2}
we have \sqrt{-12} and that doesn't give a real solution
therefor there are no real solutions
but if you want to solve fully
x=\frac{ 2+/-2\sqrt{-3} }{2}
i=\sqrt{-1}
x=\frac{ 2+/-2i\sqrt{3} }{2}
x=1+/-i\sqrt{3}
x=1-i\sqrt{3} or x=1+i\sqrt{3} (those are the 2 numbers)

 





6 0
3 years ago
Find the value of A<br> A: 18<br> B: 21<br> C: 20<br> D: 17
AnnZ [28]

These are vertical angles so they are equal so

6a +  11  = 2a + 83  

now solve for a

6 0
3 years ago
Read 2 more answers
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