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Finger [1]
3 years ago
10

Don scored 10 points higher than Rick on a test. Jackie scored 8 points less than Rick and Jared scored 3 points less than Jacki

e. The total score of all 4 of them combined was 315.
(A) Write an equation to represent this situation. (Define the variables you are using)

(B) Solve the equation and list everyone's score.

(C) Show how you will check your answer to see if you are correct.
Mathematics
1 answer:
Mrac [35]3 years ago
4 0
I used R for Rick since I am putting everything in Rick's case. The equation would be (R+10)+(R-8)+(R-11)=315.
Once you add the same terms you end with 4R-9=315
You add 9 to both sides
4R=324
Then divide
R=81
For Don, since his is ten point higher, his would be 91.
Rick is 81.
Jackie would be 73 since it is 8 points less.
And Jared would be 70 since it is 3 point less.
Check by adding; 81+91+73+70=315
Tell me if this helps.
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16 teams In a football league, each team plays each other twice , how many games are there in the football league in total ?
Brilliant_brown [7]

Answer:

120 games.

Step-by-step explanation:

We have been given that there are 16 teams in a football league. Each team plays each other twice. We are asked to find total number of games are there in the football league.

We will use formula \frac{n(n-1)}{2} to solve our given problem.

Each team will play matches with one team less as it will not play match with itself.

We will divide all number of matches by 2 to avoid repetition.

\frac{16(16-1)}{2}=\frac{16(15)}{2}=8*15=120

Therefore, there are 120 games in the football league.

4 0
3 years ago
HELP!!!
olga55 [171]

Answer:

  a) 236/100 = 2.36

  b) 101/100 = 1.01

  c) 814/100 = 8.14

Step-by-step explanation:

The divisor in each case is already a factor of 100, so multiply the numerator and denominator by the number that will make the denominator 100. Then add 100 times the integer to the numerator of the fraction.

a) 2 9/25 = (200 +9·4)/(25·4) = 236/100 = 2.36

b) 1 1/100 = (100 +1)/100 = 101/100 = 1.01

c) 8 7/50 = (800 +7·2)/(50·2) = 814/100 = 8.14

____

Since each of these fractions has a denominator of 100, the decimal can be written by putting the least significant digit of the numerator in the hundredths place of the decimal number.

For example, for 236/100, putting 6 in the hundredths place puts 3 in the tenths place and 2 in the units place for a decimal number of 2.36.

5 0
3 years ago
How many terms are in the expression: 12p + 8m + 2
lidiya [134]
Use Socratic it helps
7 0
3 years ago
2 3/4 ÷ 1 7/8=?<br> pls help
Anna11 [10]

Answer:

77/32 or 2 13/32

Step-by-step explanation:

First, convert the mixed numbers into improper fractions, 11/4*7/8

Next, you can just multiply the fractions for your answer!

Hope this helped<3

7 0
2 years ago
A certain region currently has wind farms capable of generating a total of 2200 megawatts (2.2 gigawatts) of power. Assuming win
sveta [45]

Answer:

<u>The correct answer is A. 4,818'000,000 kilowatt-hours per year and B. 481,800 households.</u>

Step-by-step explanation:

1. Let's review the information provided to us for solving the questions:

Power capacity of the wind farms = 2,200 Megawatts or 2.2 Gigawatts

2. Let's resolve the questions A and B:

Part A

Assuming wind farms typically generate 25​% of their​ capacity, how much​ energy, in​ kilowatt-hours, can the​ region's wind farms generate in one​ year?

2,200 * 0.25 = 550 Megawatts

550 Megawatts = 550 * 1,000 Kilowatts = 550,000 Kilowatts

Now we calculate the amount of Kilowatts per hour, per day and per year:

550,000 Kw generated by the farms means that are capable of produce 550,000 kw per hour of energy

550,000 * 24 = 13'200,000 kilowatt-hours per day

<u>13'200,000 * 365 = 4,818'000,000 kilowatt-hours per year</u>

Part B

Given that the average household in the region uses about​ 10,000 kilowatt-hours of energy each​ year, how many households can be powered by these wind​ farms?

For calculating the amount of households we divide the total amount of energy the wind farms can generate (4,818'000,000 kilowatt-hours) and we divide it by the average household consumption (10,000 kilowatt-hours)

<u>Amount of households =  4,818'000,000/10,000 = 481,800</u>

8 0
3 years ago
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