Please help I don't understand. Thank you I will give you the brainliest

5)

Natalija [7]

Answer:

i think the 2nd one

Step-by-step explanation:

7 0

2 years ago

What are the zeros of the function? what are their multiplicities? f(x)=x^4-4x^3+3x^2

-Dominant- [34]

Since each term contains x, x= 0 is one answer Also as x^2 is a factor it has duplicity 2.
Factoring:-

x^2 (x^2 - 4x + 3) = 0
x^2( x - 3)(x - 1) = 0

so x = 3 and x = 1 are also zeros

Answer:- x = 0 (duplicity 2), x = 1 and x = 3.

4 0

2 years ago

I’ll mark youyou brainlist

diamong [38]

It’s 148 cuz of linear pair.

3 0

2 years ago

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Am I correct with this?

Shkiper50 [21]

Answer:

no

Step-by-step explanation:

u can cut the trapesoid in half and make it into a rectangle then get ur answer

7 0

3 years ago

Which equation represents a graph with a vertex at (–3, 2)?

lesya [120]

We will proceed to find the equations in the vertex form in each case

Part a) $y= 4x^{2}+24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}+24x$

Factor the leading coefficient

$y-38= 4(x^{2}+6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}+6x+9)$

$y-2= 4(x+3)^{2}$

$y= 4(x+3)^{2}+2$

the vertex is the point $(-3,2)$

Part b) $y=4x^{2}-24x+38$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-38= 4x^{2}-24x$

Factor the leading coefficient

$y-38= 4(x^{2}-6x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-38+36= 4(x^{2}-6x+9)$

$y-2= 4(x-3)^{2}$

$y= 4(x-3)^{2}+2$

the vertex is the point $(3,2)$

Part c)  $y=4x^{2}+12x+2$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-2= 4x^{2}+12x$

Factor the leading coefficient

$y-2= 4(x^{2}+3x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-2+9= 4(x^{2}+3x+2.25)$

$y+7= 4(x+1.5)^{2}$

$y= 4(x+1.5)^{2}-7$

the vertex is the point $(-1.5,7)$

Part d) $y=4x^{2}+16x+13$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$y-13= 4x^{2}+16x$

Factor the leading coefficient

$y-13= 4(x^{2}+4x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$y-13+16= 4(x^{2}+4x+4)$

$y+3= 4(x+2)^{2}$

$y= 4(x+2)^{2}-3$

the vertex is the point $(-2,-3)$

therefore

the answer is

$y= 4x^{2}+24x+38$

3 0

3 years ago

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