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2 years ago

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Mathematics

1 answer:

Natali5045456 [20]2 years ago

6 0

The answer is 19 x yay

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Harold and his friend both enjoy running long distances.Yesterday Harold ran 8 2/4 miles and his friend ran 4 3/4 miles. How man

andriy [413]

Answer:

Harold ran $3\frac{3}{4}\ miles$ more than his friend.

Step-by-step explanation:

Given:

Number of miles Harold ran = $8\frac{2}{4}\ miles$

$8\frac{2}{4}\ miles$ can be Rewritten as $\frac{34}{4}\ miles$

Number of miles Harold ran = $\frac{34}{4}\ miles$

Number of miles his friend ran = $4\frac{3}{4}\ miles$

$4\frac{3}{4}\ miles$ can be Rewritten as $\frac{19}{4}\ miles$

Number of miles his friend ran = $\frac{19}{4}\ miles$

We need to find number of miles Harold ran more than his friend.

Solution:

Now we can say that;

To find the number of miles Harold ran more than his friend we need to subtract Number of miles his friend ran from Number of miles Harold ran.

framing in equation form we get;

the number of miles Harold ran more than his friend = $\frac{34}{4}-\frac{19}{4} =\frac{34-19}{4} = \frac{15}{4}\ miles$

$\frac{15}{4}\ miles$ can be Rewritten as $3\frac{3}{4}\ miles$

the number of miles Harold ran more than his friend = $3\frac{3}{4}\ miles$

Hence Harold ran $3\frac{3}{4}\ miles$ more than his friend.

4 0

2 years ago

Your teacher gives you a graph of the parent function y = x^2 and the graph of another function. You notice that the new functio

Arlecino [84]

It’s either B or C if it’s being translated to the right it’s B but if it’s being translated to the left it’s C

7 0

2 years ago

Read 2 more answers

How do you find the missing side??

guapka [62]

Answer:

$\boxed{\ell = 12}.$

Step-by-step explanation:

Let $\ell$ denote the length of the missing side. Since $\triangle ABC$ and $\triangle AXY$ share one vertex and $\overline{XY}\parallel \overline{BC}$ , these triangles are similar. This means that:

$\dfrac{AX}{AB} = \dfrac{AY}{AC} \iff \dfrac{\ell}{18+\ell} = \dfrac{14}{14+21} \iff\dfrac{\ell}{18+\ell} = \dfrac{14}{35}.$

We now multiply both sides by $18+\ell$ and solve the equation:

$\dfrac{\ell}{18+\ell} = \dfrac{14}{35} \iff \ell = \dfrac{36}{5} + \dfrac{14}{35}\ell \iff \ell \left(1-\dfrac{14}{35}\right) = \dfrac{36}{5} \iff \dfrac{3}{5}\ell = \dfrac{36}{5}.$