-2,3 is (x1,y1) and (4,-5) is (x2,y2) so you do y2-y1/x2-x1
y2-y1 is -5-3 which is -8 and x2-x1 is 4-(-2) which is 6 so you get
-8/6= -4/3
You can solve for sides of a triangle using the following equation.
A = arccos (b^2 + c^2 - a^2/2bc)
And likewise for other variables by moving the letters.
Ultimately, in this problem you get the following angle measures:
15.87
23.97
140.16
Hello! I can help you! First things first, because they are both the same angles on opposite sides, let's set this up in the form of an equation and solve for "x". It would be set up like this:
2x + 20 = 3x - 30
You see up top that it says 2(x + 10). What you would do is multiply what's in the parenthesis by 2, in order to get 2x + 20. Then put the equal sign and write 3x - 30. Subtract 3x from both sides to get -1x + 20 = -30. Subtract 20 from both sides to get -1x = -50. Divide each side by -1 to isolate the "x". In this case, because you are dividing a negative number by a negative number, your quotient will be positive. -50/-1 is 50. Let's plug in the value as "x" and see if it works. 50 * 2 is 100. 100 + 20 is 120. 50 * 3 is 150. 150 - 30 is 120. 120 = 120. There. x = 50.
Answer:
"false" I believe if wrong srry
