Question

Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×b+50 approximates the relationship between scores on the two tests. use the summary statistics for a sample of students who took test b to determine the summary statistics for equivalent scores on test
a. lowest score equals= 2121 mean equals= 2929 standard deviation equals= 22 q3 equals= 2828 median equals= 2626 iqr equals= 66 find the summary statistics for equivalent scores on test
a. lowest scoreequals= nothing meanequals= nothing standard deviationequals= nothing q3equals= nothing medianequals= nothing iqrequals= nothing

Answer 1

Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.

Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:

The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the lowest score of test A is given by 40(21) + 50 = 890

Therefore, the lowest score of test A is 890.



Part B:

The mean score is a measure of location, so both addition and multiplying the mean score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the mean score of test A is given by 40(29) + 50 = 1,210

Therefore, the mean score of test A is 890.



Part C:

The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50 to the result will not affect the standard deviation of test A.

Thus, the standard deviation of test A is given by 40(2) = 80

Therefore, the standard deviation of test A is 80.



Part D

The Q3 score is a measure of location, so both addition and multiplying the Q3 score of test B by 40 and adding 50 to the result will affect the Q3 score of test A.

Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170

Therefore, the Q3 score of test a is 1,170.



Part E:

The median score is a measure of location, so both addition and multiplying the median score of test B by 40 and adding 50 to the result will affect the median score of test A.

Thus, the median score of test A is given by 40(26) + 50 = 1,090

Therefore, the median score of test A is 1,090.



Part F:

The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50 to the result will not affect the IQR of test A.

Thus, the IQR of test A is given by 40(6) = 240

Therefore, the IQR of test A is 240.