How do I solve this finding the first four of the sequence?

Pleasd help me solve

krok68 [10]

Step-by-step explanation:

y = 2x

if x = 1 y = 2(1) = 2

if x = 2 y = 2(2) =4

4 0

3 years ago

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Can someone plz solve this for me??

denis-greek [22]

Answer:

-2 x 3 + t = -6

Step-by-step explanation:

8 0

3 years ago

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Trials in an experiment with a polygraph include 98 results that include 24 cases of wrong results and 74 cases of correct resul

madreJ [45]

Answer:

$z=\frac{0.755 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-1.114$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of successes is not significantly less than 0.8 or 80%

Step-by-step explanation:

Data given and notation

n=98 represent the random sample taken

X=74 represent the number of cases correct

$\hat p=\frac{74}{98}=0.755$ estimated proportion of successes

$p_o=0.8$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of successes is less than 0.8.:

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.755 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-1.114$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of successes is not significantly less than 0.8 or 80%

5 0

3 years ago

A produce store offers red and green apples. In one morning they sold 39 apples total, if 9 of the apples they sold were red, wh

kap26 [50]

Red apples + green apples = 39 apples
9 red apples + green apples = 39 apples
OR
Red apples = X
Green apples = Y

X + Y = 39
9+Y= 39
Y= 30 (Subtract 9 from both sides)

ratio= 9/30 or 3/10 (reduce the fraction by dividing by 3)

4 0

3 years ago

One hundred student. named their favorite vegetable.One half named"carrots"one fourth named "broccoli"one tenth named "peas"and

vagabundo [1.1K]

Carrots: 50/100
Broccoli: 25/100
Peas: 10/100
Celery: 15/100

8 0

3 years ago