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4 years ago

14

When a machine is used to perform a task, work output is always more than work input. please select the best answer from the cho

ices provided t f?

1 answer:

Maurinko [17]4 years ago

5 0

Properly input current above 40 voltage or 100 for example elecrical fan machine is used to perform a task, work output is always more than work

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Snowcat [4.5K]

Answer:

1. The conversation of momentum is when a person or object has momentum and transfers it to another person or object.

Explanation:

2. Like if someone is on a swing and kicks someone in front of him. He stops and the kid in front of him falls over because the momentum was transferred.

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3 years ago

Read 2 more answers

1. A 2500 kg car enters a curve with a radius of 45 m If the car is moving at a speed of 35 m's, what is the

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3 years ago

Explain at least 3 primary and secondary online sources of data<br>

Slav-nsk [51]

Answer And Explanation:

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4 years ago

Which of the following describes the electron sharing between hydrogen and fluorine A.Hydrogen and fluorine share one electron w

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Hydrogen has one electron in its outermost shell, while fluorine has seven electron in its outermost shell, hence both hydrogen and fluorine needs a single electron to complete its outermost shell.
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4 years ago

20.0 -kg cannonball is fired from a cannon with muzzle speed of 1000m/s at an angle of 37.0° with the horizontal. A second ball

Dovator [93]

The mechanical energy for the first and the second ball is

$10 ^{7} \: joules.$

Mass of the first ball = 20 kg

The initial speed at which a cannonball is fired from a cannon =1000 m/s

The angle made by the cannonball while being fired from the cannon = 37°

The maximum height reached by the first ball is,

$= \frac{ u {}^{2} _{1}sin {}^{2} θ}{2g}$

$= \frac{ {1000}^{2} sin {}^{2}37°}{2 \times 9.8}$

$= 18478.69 \: m$

The maximum height of the first cannonball is 17478.69 m.

The initial speed at which a cannonball is fired from a cannon =1000 m/s

The angle made by the cannonball while being fired from the cannon = 90 °

$= \frac{ u {}^{2} _{2}sin {}^{2} θ}{2g}$

$= \frac{ 1000{}^{2}sin^{2} 90°}{2 \times 9.8}[tex] = 51020.41 \: m$

For the first ball, total mechanical energy= Potential energy at maximum height + kinetic energy at the maximum height

So, the total mechanical energy is,

= mgh \: + \frac{1}{2}mv {}^{2} _{x}[/tex]

$= 20 \times 9.8 \times 18478.64 \times \frac{20}{2} (1000 \: cos37 °)$

$= 10 ^{7} The potential energy at the maximum height, = m _{2}gh$

$= 20 \times 9.8 \times 51020.41$

$= 10 ^{7} \:J$

Therefore, the total mechanical energy for the first and the

$\:second \: cannonball \: is \: 10 ^{7} \:joules.$

To know about energy, refer to the below link:

brainly.com/question/1932868

#SPJ4

5 0

2 years ago