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4 years ago

14

When a machine is used to perform a task, work output is always more than work input. please select the best answer from the cho

ices provided t f?

1 answer:

Maurinko [17]4 years ago

5 0

Properly input current above 40 voltage or 100 for example elecrical fan machine is used to perform a task, work output is always more than work

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The density of dry air at room temperature and atmospheric pressure Is 1.2 kg m-3. What volume would 6 kg of dry air occupy unde

larisa [96]

Answer:

V = 5 m³

Explanation:

The density of air, d = 1.2 kg/m³

Mass of the dry air, m = 6 kg

We need to find the volume o the gas. We know that, the density of an object is given by mass divided by its volume. So,

$d=\dfrac{m}{V}\\\\V=\dfrac{m}{d}\\\\V=\dfrac{6}{1.2}\\\\V=5\ m^3$

So, the volume of the dry air is 5 m³.

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3 years ago

What is the mechanical advantage of an inclined plane that has a length of 9 feet and a height of 3 feet?

Rainbow [258]

Answer:

it would be 3

Explanation:

because you have to divide the length by the height of the incline.

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3 years ago

Read 2 more answers

Where does Amino acid come from?

Vesna [10]

Answer:

The best sources of essential amino acids are animal proteins like meat, eggs and poultry. When you eat protein, it's broken down into amino acids, which are then used to help your body with various processes such as building muscle and regulating immune function ( 2 ).

Explanation:

6 0

3 years ago

Interactive Solution 22.43 provides one model for solving this problem. The maximum strength of the earth's magnetic field is ab

laila [671]

Answer:

427097

Explanation:

V = Voltage = 170 V

B = Magnetic field = $6.9\times 10^{-5}\ T$

f = Frequency = 54.1 Hz

A = Area = $0.024\ m^2$

Number of turns is given by

$N=\dfrac{V\sqrt{2}}{BA2\pi f}\\\Rightarrow N=\dfrac{170\sqrt{2}}{6.9\times 10^{-5}\times 0.024\times 2\pi\times 54.1}\\\Rightarrow N=427096.933536\approx 427097\ turns$

Number of turns is 427097

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4 years ago

One star has a magnitude of -1.5 and another star has a magnitude of +0.6. What is the ratio of brightness of these two stars?

In-s [12.5K]

Answer:

7

Explanation:

$The \ ratio \ of \ brightness \ of \ these \ two \ stars \ is:$

$\dfrac{b_{first \ star }}{b _{second \ star }}= 2.512^{(m_{(second \ star )} - (m_{first \ star } ))}$

$\dfrac{b_{first \ star }}{b _{second \ star }}= 2.512^{(0.6 - (-1.5 ))}$

$\dfrac{b_{first \ star }}{b _{second \ star }}= 2.512^{(2.1)}$

$\dfrac{b_{first \ star }}{b _{second \ star }}= 6.9$

$\mathbf{\dfrac{b_{first \ star }}{b _{second \ star }} \simeq 7}$

4 0

3 years ago