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ratelena [41]
2 years ago
15

Enter a rational equation for the real-world application. Do not solve.

Mathematics
1 answer:
ratelena [41]2 years ago
3 0

Answer:

data:image/png;base64,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Someone could help me with problem 3-76 (b) pls
kupik [55]

Answer:

ok so you see the equation at the top... you are going to "plug in" the number in the "in" row to get the "out number

Step-by-step explanation:

example

in: 4

-2(-4)+1

8+1

9

so for the out row under -4 you would put 9

-2(-3)+1

6+1

7

so for the out row under 3 you would put 7

5 0
3 years ago
Read 2 more answers
What is half of 7 5/8 and 5 3/8
meriva

Answer:

6.5

Step-by-step explanation:

7 5/8 + 5 3/8= 13

13/2=6.5

5 0
3 years ago
Write down in terms of N and expression for the nth term of the following sequence 25 20 15 10 5
GREYUIT [131]

Answer:

30x-5

Step-by-step explanation:

25-5=20

20-5=15

-5  -10  -15  -20  -25

25  20  15   10     5

I hope that helped you

8 0
3 years ago
How many times greater is 130,000,000 than 64,800,000?
insens350 [35]
\frac{130,000,000}{64,800,000} = \frac{1,300}{648} =\boxed {2.00617283951}
4 0
3 years ago
Help please! This is a Calculus AB question!
Lynna [10]

Answer:

½ ln 3

Step-by-step explanation:

∫ sec²x / tan x dx

If u = tan x, then du = sec²x dx.

∫ du / u

ln|u| + C

ln|tan x| + C

Evaluate between π/4 and π/3.

ln|tan(π/3)| + C − (ln|tan(π/4)| + C)

ln|√3| + C − ln|1| − C

ln(√3)

½ ln 3

7 0
3 years ago
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