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2 years ago

The side lengths of a triangle are 5, 8, and 12. Is this a right triangle?

Mathematics

2 answers:

katovenus [111]2 years ago

6 0

Answer:

Step-by-step explanation:

lyudmila [28]2 years ago

4 0

Answer: No, it is not a right triangle.

===================================================

Let

a = 5
b = 8
c = 12

Let's see if a^2 + b^2 = c^2 is a true equation. If so, then we have a right triangle.

a^2 = 5^2 = 25

b^2 = 8^2 = 64

a^2+b^2 = 25+64 = 89

c^2 = 12^2 = 144

We see that a^2+b^2 = 89, but c^2 = 144. So a^2+b^2 = c^2 is a false equation when (a,b,c) = (5,8,12). Therefore, this is not a right triangle.

Side note: Because c^2 is larger than a^2+b^2 in this case, this means we have an obtuse triangle.

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Constant of proportionality y = 1/4 x

Dovator [93]

Answer:

The constant of proportionality is 1/4.

Step-by-step explanation:

4 0

2 years ago

PLEASE HELP/ANSWER! From 1980 to 1990, Lior’s weight increased by 25%. If his weight was k kilograms in 1990, what was it in 198

Elena-2011 [213]

The weight in 1980 is $\frac{4k}{5}$ kilograms

Solution:

From 1980 to 1990, Lior’s weight increased by 25%

His weight is "k" kilograms in 1990

To find: weight in 1980

This is a percentage increase problem

Let "x" be the weight in kilograms in 1980

The percentage increase is given by formula:

$\text{Percentage increase } = \frac{\text{Final value - initial value}}{\text{initial value}} \times 100$

Here,

Initial value in 1980 = x

Final value in 1990 = k

Percentage increase = 25 %

Substituting the values in formula,

$25 = \frac{k-x}{x} \times 100\\\\25x = 100(k-x)\\\\x = 4(k-x)\\\\x = 4k - 4x\\\\5x = 4k\\\\x = \frac{4k}{5}$

Thus the weight in kilograms in 1980 is $\frac{4k}{5}$

7 0

3 years ago

Audryn left a $12 tip on a $68.73 restaurant bill. What percent tip did she leave? Round to the nearest tenth of a percent.

Fiesta28 [93]

So, if we take 68.73 to be the 100%, what is 12 in percentage off of it?

$\bf \begin{array}{ccll}
amount&\%\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
68.73&100\\
12&p
\end{array}\implies \cfrac{68.73}{12}=\cfrac{100}{p}\implies p=\cfrac{12\cdot 100}{68.73}$

seems Audryn is being generous, she probably got the silverware and the maple leaves tablecloth.

4 0

3 years ago

5. The heights of 500 female students are measured, half of whom are college students and half of whom are second-grade students

AysviL [449]

Using statistical concepts, it is found that:

2 modes would be expected for the distribution.
The distribution would be symmetric.

-------------------------------

Heights are traditionally normally distributed, which is a symmetric distribution.
Second-grade students are considerably shorter than college students, so there would be two modes.
Both distributions, for the height of second grade and of college students, are normal, which is symmetric, thus the combined distribution will also be symmetric.

A similar problem is given at brainly.com/question/13460485

4 0

2 years ago

An employee earns a 12% commission rate on the cameras he sells. If he earns $384 in commission, what were his total sales?

Vlad1618 [11]

I do questions like these a little different than most people so...

384/12= 32 (32 is 1% of his sales)
32*100= 3200

His total sales were $3200.

4 0

2 years ago

Read 2 more answers