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Vilka [71]
2 years ago
5

A soap bubble, when illuminated at normal incidence with light of 463 nm, appears to be especially reflective. If the index of r

efraction of the film is 1.35, what is the minimum thickness the soap film can be if it is surrounded by air
Physics
1 answer:
Sedbober [7]2 years ago
5 0

Answer:

the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

Explanation:

Given the data in the question;

wavelength of light; λ = 463 nm = 463 × 10⁻⁹ m

Index of refraction; n = 1.35

Now, the thinnest thickness of the soap film can be determined from the following expression;

t_{min = ( λ / 4n )

so we simply substitute in our given values;

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = ( 463 × 10⁻⁹ m ) / 5.4

t_{min = ( 463 × 10⁻⁹ m ) / 4(1.35)

t_{min = 8.574 × 10⁻⁸ m

t_{min = 85.74 × 10⁻⁹ m

t_{min = 85.74 nm

Therefore, the minimum thickness the soap film can be if it is surrounded by air is 85.74 nm

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