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3 years ago

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Feng has a toy car collection he keeps 324 of the toy cars on his wall which is 81% of his entire collection what is the total n

umber of toy cards in his collection

1 answer:

jeka943 years ago

7 0

Answer:

400

Step-by-step explanation:

YOU DON'T NEED ONE JUST TYPE THE ANSWER IN.

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I NEED THIS QUICK PLEASE ILL MARK YOUR BRAINLY

ziro4ka [17]

Answer:

75 & 21

Check:

75 + 21 = 96

21 * 4 - 9 = 75

Correct!

7 0

2 years ago

Read 2 more answers

I need help please please

xxTIMURxx [149]

Answer:

reflection then transition

Step-by-step explanation:

because ummm for it to get to one it is reflected then to get to 3 it is transitioned

8 0

2 years ago

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Find cp if so =rs 800 and loss% = 10%

rjkz [21]

Step-by-step explanation:

Sp = rs 800

loss = 10%

Cp = ?

we know that,

cp= sp×100÷ 100-L%

= 800×100÷100-10

= 80000÷90

= 888.89#

3 0

3 years ago

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A certain kind of sheet metal has, on average, 3 defects per 18 square feet. Assuming a Poisson distribution, find the probabili

Fofino [41]

Answer:

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given time interval.

In this problem, we have that:

3 defects per 18 square feet.

So for 31 square feet, we have to solve a rule of three

3 defects - 18 square feet

x defects - 31 square feet

$18x = 3*31$

$x = \frac{31*3}{18}$

$x = 5.17$

So $\mu = 5.17$

Assuming a Poisson distribution, find the probability that a 31 square foot metal sheet has at least 4 defects.

Either it has three or less defects, or it has at least 4 defects. The sum of the probabilities of these events is decimal 1.

So

$P(X \leq 3) + P(X \geq 4) = 1$

We want $P(X \geq 4)$

So

$P(X \geq 4) = 1 - P(X \leq 3)$

In which

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-5.17}*(5.17)^{0}}{(0)!} = 0.0057$

$P(X = 1) = \frac{e^{-5.17}*(5.17)^{1}}{(1)!} = 0.0294$

$P(X = 2) = \frac{e^{-5.17}*(5.17)^{2}}{(2)!} = 0.0760$

$P(X = 3) = \frac{e^{-5.17}*(5.17)^{3}}{(3)!} = 0.1309$

So

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0057 + 0.0294 + 0.0760 + 0.1309 = 0.242$

Finally

$P(X \geq 4) = 1 - P(X \leq 3) = 1 - 0.242 = 0.758$

75.8% probability that a 31 square foot metal sheet has at least 4 defects.

8 0

3 years ago

Three different equations that have x=5 as a solution

gulaghasi [49]

Answer:

The easiest ways to do this is to add, subtract, multiply, or devide 5 from a number, do that operation to x, and set that number as the equivelent.

For example

3 * 5=15

so

3x=15

4 0

3 years ago