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vodomira [7]
3 years ago
10

Give the half equation to show what happens to oxygen when it is rusting

Chemistry
1 answer:
ycow [4]3 years ago
3 0

Answer:

½O 2 + 2e - + H 2O → 2OH.

Explanation:

Redox reactions - Higher

In terms of electrons:

oxidation is loss of electrons

reduction is gain of electrons

Rusting is a complex process. The example below show why both water and oxygen are needed for rusting to occur. They are interesting examples of oxidation, reduction and the use of half equations:

iron loses electrons and is oxidised to iron(II) ions: Fe → Fe2+ + 2e-

oxygen gains electrons in the presence of water and is reduced: ½O2 + 2e- + H2O → 2OH-

iron(II) ions lose electrons and are oxidised to iron(III) ions by oxygen: 2Fe2+ + ½O2 → 2Fe3+ + O2-

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What mass of CO2 would be needed to weigh out to make 10.5 moles of carbon dioxide? (round answer to nearest tenth)
melamori03 [73]

The mass of carbon dioxide that would be needed to weigh is 462 grams.

Given:

10.5 moles of carbon dioxide.

The periodic table

To find:

The mass of carbon dioxide would be needed to weigh out to make 10.5 moles of carbon dioxide.

Solution:

Mass of carbon dioxide needed = m

Moles of carbon dioxide needed = 10.5 mol

The molar mass of carbon dioxide = M

The atomic mass of carbon atom = 12.011 g/mol

The atomic mass of oxygen atom = 15.999 g/mol

M = 1\times 12.011 g/mol+2\times 15.999 g/mol\\\\=44.009 g/mol

The moles of carbon dioxide will be given as:

10.5 mol=\frac{m}{44.009 g/mol}\\\\m=10.5 mol\times 44.009 g/mol=462.0945 g\approx 462 g

The mass of carbon dioxide that would be needed to weigh is 462 grams.

Learn more about the moles of substance here:

brainly.com/question/2293005?referrer=searchResults

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When sodium metal is added to water, an orange flame is observed on the metal surface. Based on this observation, what can best
pickupchik [31]
All you can conclude is that something must be burning with an orange flame.

Actually, the "something" that must be burning is the hydrogen that is produced when the sodium reacts with the water:

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So much heat is produced that the hydrogen catches fire and some of the sodium evaporates into the flame.

The electrons in the sodium atoms get "excited" in the flame. When they drop back to a lower energy level, they emit energy in the form of an orange-yellow light.
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