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wolverine [178]
2 years ago
8

Why should you not choose a point on the line to find the direction of shading in an inequality?

Mathematics
2 answers:
PIT_PIT [208]2 years ago
6 0

Answer:

Because we know for a fact that the line has a correct answer. Plus, if you choose a point on the line then it will not give you the visual side of which is correct and which is wrong.

Step-by-step explanation:

larisa86 [58]2 years ago
6 0

Answer:

Because a line will always have a correct answer. If i choose a point on the line then it won't give you the visual side that is correct and which is wrong.

Step-by-step explanation:

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PLEASE HELP ASAP!!!!! For the function f(x) = x2 + 3, what are the outputs for the inputs -3, 2, 0, and 5?
DaniilM [7]
Switch the x for -3, 2, 0, and 5 so the answer will be B
6 0
3 years ago
Write the equation of the tangent line to x2+y2=41 at the point (-4,5)
AnnyKZ [126]

Answer:

As attached

Step-by-step explanation:

6 0
3 years ago
How do you do this?PLZ HELP
Alisiya [41]
3(x^2+10x+5)-5(x-k)=
3x^2+30x+15-5x+5k=
3x^2+25x+15+5k

for this to be divisible by x every term must include x or get eliminated

the problematic terms are 15 and 5k
to eliminate them they must equal 0 when added:
15+5k=0
5k=-15
k=-3

so A) -3 is the solution
5 0
3 years ago
Which statement is true about the graphed function?
yarga [219]

Answer: Choice D)

F(x) > 0 over the inverval (-infinity, -4)

Translation: The y or f(x) values are positive whenever x < -4.

========================================================

Further Explanation:

Recall that y = f(x), so if we say something like f(x) < 0 then we mean y < 0. Choice A is false because points on the curve to the left of x = -4 have positive y coordinates. Similar reasoning applies to choice B as well.

Choice C is false because while the interval (-infinity, -4) is above the x axis, the portion from x = -4 to x = -3 is below the x axis.

Choice D is true because everything to the left of x = -4 is above the x axis. Pick any point on the blue curve that is to the left of x = -4. This point will be above the horizontal x axis. Keep in mind that the parenthesis notation attached to the -4 means we dont include -4 as part of the interval.

4 0
3 years ago
Read 2 more answers
Pleases someone explain
Nikolay [14]

When you have a negative exponent, you move the base with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

\frac{1}{y^{-2}} =\frac{y^2}{1} or y^2

2x^{-3} or \frac{2^1x^{-3}}{1} =\frac{2}{x^3}

\frac{1}{x^{-5}} =x^5

When a base with an exponent is divided by a base with an exponent, you subtract the exponents together. (But you can only combine the exponents when the bases are the same)

For example:

\frac{x^2}{y}   (can't combine because they have different bases of y and x)

\frac{x^5}{x^3} =x^{(5-3)}=x^2

\frac{2^2}{2} =2^{(2-1)}=2^1 = 2

When you multiply an exponent directly to a base with an exponent, you multiply the exponents together.

For example:

(x^2)^3=x^{(2*3)}=x^6

(y^2)^{10}=y^{(2*10)}=y^{20}

\frac{2e^0}{(e^{-3})^2}     First multiply the exponents together in the denominator

\frac{2e^0}{e^{(-3*2)}}= \frac{2e^0}{e^{-6}}        Now subtract the exponents together

2e^{(0-(-6))}  (two negative signs cancel each other out and become positive)

2e^{(0+6)}

2e^6

7 0
3 years ago
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