5 7/8 x (2 4/5 ÷ 7) AHH HELP I'M TO STUPID FOR THIS
1 answer:
Convert 5 7/8 to an improper fraction. Use this rule: a b/c = ac + b/c
5 × 8 + 7/8 × 2 4/5 ÷ 7
Simplify 5 × 8 to 40
40 + 7/8 × 2 4/5 ÷ 7
Simplify 40 + 7 to 47
47/8 × 2 4/5 ÷ 7
Convert 2 4/5 to an improper fraction using the same rule from the previous step.
47/8 × 2 × 5 + 4/5 ÷ 7
Simplify 2 × 5 to 10
47/8 × 10 + 4/5 ÷ 7
Simplify 10 + 4 to 14
47/8 × 14/5 ÷ 7
Use this rule: a ÷ b/c = a × c/b
47/8 × 14/5 × 1/7
Proceed to use this rule: a/b × c/d = ac/bd
658/8 × 5 × 7
Simplify 8 × 5 × 7 to 280
658/280
Simplify
47/20
Convert to mixed fraction
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Answer:
88
Step-by-step explanation:
Write the expression for the sum in the relation you want.
Sn = u1(r^n -1)/(r -1) = 2.1(1.06^n -1)/(1.06 -1)
Sn = (2.1/0.06)(1.06^n -1) = 35(1.06^n -1)
The relation we want is ...
Sn > 5543
35(1.06^n -1) > 5543 . . . . substitute for Sn
1.06^n -1 > 5543/35 . . . . divide by 35
1.06^n > 5578/35 . . . . . . add 1
n·log(1.06) > log(5578/35) . . . take the log
n > 87.03 . . . . . . . . . . . . . . divide by the coefficient of n
The least value of n such that Sn > 5543 is 88.
