Answer:
length of side of square = (4x - 5) inches
Step-by-step explanation:
We are given;
Area of square = 16x² – 40x + 25
Let's find the roots of this quadratic equation [-b ± √(b² - 4ac)]/2a
Thus;
x = [-(-40) ± √((-40)² - 4(16 × 25)]/(2×16)
x = [40 ± √(1600 - 1600)]/32
x = (40 ± 0)/32
x = 40/32
x = 5/4
Thus, the factors of the polynomial are;
(4x - 5)²
So,
Area = 16x² – 40x + 25 = (4x - 5)²
Since, the right hand side is (4x - 5)² and area of square is (length of side)², thus we can say that length of side of square is (4x - 5) inches
Answer:
X^2 + 10 + 24
Step-by-step explanation:
Answer: there are three of the holidays
Step-by-step explanation:
The prime numbers through 31 include 2,3,5,7,11,13,17,19,23,29,31,and 37 so therefore three of the holidays (Martin Luther, Easter, and Thanksgiving) fall on days that are prime numbers
Answer:
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Answer:
85.5 minutes
Step-by-step explanation:
The amount of an element that will remain after time t can be expressed as a function of initial amount N0, time t, and half life th as;
Nt = N0 × e^(-λt)
Where;
Decay constant λ = ln(2)/th, substituting into the equation;
Nt = N0 × e^(-ln(2)t/th)
We need to make t the subject of formula;
Nt/N0 = e^(-ln(2)t/th)
ln(Nt/N0) = -ln(2)t/th
t = ln(Nt/N0) ÷ -ln(2)/th
Given;
Initial amount N0 = 760g
Final amount Nt = 11 g
Half life th = 14 minutes
the nearest tenth of a minute, would it take the element to decay to 11 grams can be derived using the formula;
t = ln(Nt/N0) ÷ -ln(2)/th
Substituting the given values;
t = ln(11/760) ÷ -ln(2)/14
t = 85.5 minutes
