Functions are used to represent graphs, and vice versa.
The function represented by the graph is 
The graph (see attachment) is an absolute value graph.
An absolute value graph is represented as:

Where

The vertex is the minimum or the maximum point on the graph.
So, we have:

The function becomes

The function also passes through the point (-1,0).
So, we have:


Remove the absolute bracket

Subtract 3 from both sides

Divide both sides by 3

Substitute -1 for (a) in 

Hence, the function represented by the graph is 
Read more about absolute value graphs at:
brainly.com/question/3381225
Answer:
54
Step-by-step explanation:
6 x 9 = 54
she can there are
make 6 9 yards
ribbons
out of
a yard


By the remainder theorem, the remainder upon dividing a polynomial

by a linear binomial

is equal to

. Via synthetic division, we get
1 | 4 -5 6
. | 4 -1
- - - - - - - - - - -
. | 4 -1 5
which translates to

or

Indeed, when

, the first term on the right hand side vanished and we're left with 5.
Answer:
the radius of the base is equal to ![x=2\sqrt[3]{\frac{105}{\pi } }](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D)
And the height is equal to:
![y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B840%7D%7B%5Cpi%282%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%7D%7D%29%5E%7B2%7D%20%7D)
Step-by-step explanation:
We write the volume function
where x is the radius of the base and y is the height of the cylinder

The surface of a cylinder is given by
on the interval from 0 to infinity
We now determine the critical values by differentiating and making the equation equal to 0

This equation have 2 complex solutions and one real solution
![x=2\sqrt[3]{\frac{105}{\pi } }](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D)
For x=0 and infinity the equation goes to infinity also so the radius of the base is equal to ![x=2\sqrt[3]{\frac{105}{\pi } }](https://tex.z-dn.net/?f=x%3D2%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D)
And the height is equal to:
![y=\frac{840}{\pi (2\sqrt[3]{\frac{105}{\pi } })^{2} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B840%7D%7B%5Cpi%20%282%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%20%7D%20%7D%29%5E%7B2%7D%20%7D)
![y=\frac{840}{\pi(2\sqrt[3]{\frac{105}{\pi}})^{2} }](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B840%7D%7B%5Cpi%282%5Csqrt%5B3%5D%7B%5Cfrac%7B105%7D%7B%5Cpi%7D%7D%29%5E%7B2%7D%20%7D)
Answer:
The confidence interval for the true mean calorie content is

Step-by-step explanation:
In this problem we know the mean and standard deviation fo the sample, so we can compute the CI like this:

We need to determine t for 10-1=9 degrees of freedom and 99% confidence level. We look up in the t-table and the value for t is 3.2498.
Then we can calculate the limits of the CI:
