HELP ME HURRY Which graph best represents an equation with the values shown in the table?

Mathematics

1 answer:

masha68 [24]2 years ago

3 0

The first graph one

You might be interested in

Geometric Sequences Question.

g100num [7]

the common RATIO is 4

Step-by-step explanation:

sana nakatulong ito

8 0

2 years ago

Evie is wrapping a gift. The give is 12 inches long, 4 inches wide, and 6 inches tall. How much wrapping paper will Evie need?

dangina [55]

Answer:

<h2>çevirisi mi lazım sa yazabilirim</h2>

3 0

3 years ago

Read 2 more answers

Let {v1,v2,v3} be a set of vectors in Rn . If u is Span {v1,v2,v3}, show that 3u is in Span {v1,v2,v3}.(Hint: since you are told

ANTONII [103]

Answer:

See proof below

Step-by-step explanation:

We will use the hint. The statement of the hint holds true, as the linear span of a set of vectors T is equal to the set of linear combinations of vectors in T.

Denote the linear span of vectors with the curly brackets < >, that is, $span\{v_1,v_2,v_3\}:=$

Let $u\in$ , then u is a linear combination of v1,v2,v3, that is, there exist scalars $c_1,c_2,c_3\in \mathbb{R}$ such that $u=c_1v_1+c_2v_2+c_3v_3$ . Multiply by 3 in both sides to get $3u=3c_1v_1+3c_2v_2+3c_3v_3=d_1v_1+d_2v_2+d_3v_3$ , with $d_i=3c_i,i=1,2,3$

Since $c_1,c_2,c_3\in \mathbb{R}$ , $d_1,d_2,d_3\in \mathbb{R}$ as real numbers are closed under multiplication. Therefore 3u is a linear combination of the vectors $v_1,v_2,v_3$ , that is, $3u\in$