The radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit
<h3>How to determine the radius of the circle?</h3>
The circle equation of the graph is given as:
(x + 3/8)^2 + y^2 = 1
The general equation of a circle is represented using the following formula
(x - a)^2 + (y - b)^2 = r^2
Where the center of the circle is represented by the vertex (a, b) and the radius of the circle is represented by r
By comparing the equations (x - a)^2 + (y - b)^2 = r^2 and (x + 3/8)^2 + y^2 = 1, we have the following comparison
(x - a)^2 = (x + 3/8)^2
(y - b)^2 = y^2
1 = r^2
Rewrite the last equation as follows:
r^2= 1
Take the square root of both sides of the equation
√r^2 = √1
Evaluate the square root of 1
√r^2 = 1
Evaluate the square root of r^2
r = 1
Hence, the radius of the circle of the circle equation (x + 3/8)^2 + y^2 = 1 is 1 unit
Read more about circle equation at:
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Answer: 7 and 8
<u>Step-by-step explanation:</u>
Let x represent the first number, then x + 1 is the other number.
(x)² + (x + 1)² = 113
x² + x² + 2x + 1 = 113 <em>expanded (x + 1)²</em>
2x² + 2x + 1 = 113 <em>added like terms</em>
2x² + 2x - 112 = 0 <em>subtracted 113 from both sides</em>
x² + x - 56 = 0 <em> divided both sides by 2</em>
(x + 8) (x - 7) = 0 <em>factored polynomial</em>
x + 8 = 0 x - 7 = 0 <em>applied zero product property</em>
x = -8 x = 7 <em> solved for x</em>
↓
not valid since the restriction is that x > 0 <em>(a positive number)</em>
So, x = 7 and x + 1 = (7) + 1 = 8
Answer:g = 50 g
Step-by-step explanation:
She used 60% more than required ⇒ she used (1+0.60)=1.60 times what was required.
x = grams required by the recipe
80 g = 1.60x
x = (80/1.60) g = 50 g
We have slope intercept form. Parallel means the same slope, and we get to choose the intercept to fit the new point (-6,0).
y = (1/3) x + b
0 = (1/3) (-6) + b
2 = b
Answer y = (1/3) x + 2 third choice
Answer:
2 - 2 cos²x = sin x
2 = sin x + 2 cos² x
0 = -2 + sin x + 2(1 - sin² x)
0 = -2 sin² x + sin x + 2 - 2
0 = 2 sin² x - sin x 0 = sin x (2 sin x - 1)
sin x = 0 v sin x = 0.5
x10° + k.360° x1 = 0°, 360°
x2 = (180° - 0°) + k.360°
x2 = 180°
x3 = 30° + k.360°
x3 = 30°
x4 = (180° -30°) + k.360° x4 = 150°
HP: {x | 0°, 30°, 150°, 180°, 360°)
