The correct answer is the last number line because with an inequality, the "equal to" sign below the "<" or ">" means the circle should be filled in. The line is traveling in a negative direction because the inequality says that n is less than -1.

5 0

2 years ago

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Triangle A B C is shown. Angle A C B is a right angle. The length of hypotenuse A B is 12 centimeters, the length of C B is 9.8

RSB [31]

Answer: We can find angle BAC by using (1) SinA = 9.8/12

(2) CosA = 6.9/12

(3) TanA = 9.8/6.9

Step-by-step explanation: The question indicates that we have a right angled triangle ABC with the right angle at point C (that is, angle ACB is the right angle). Also the three sides have been labeled as AB equals 12 cm, CB equals 9.8 cm and AC equals 6.9 cm. Line AB has been identified as the hypotenuse and angle A (that is, BAC) is the reference angle. If angle A is the reference angle, then line CB facing angle A shall be the opposite side, while line AC is the adjacent (which lies between the reference angle and the right angle). Please see the attached diagram for details.

Having these details available, we can actually find angle A by using any of the three trigonometric ratios, since all three sides are given. Hence,

SinA = opposite/hypotenuse

SinA = 9.8/12

SinA = 0.8167

Checking with your calculator or table of values, A = 54.76 (approximately 55)

Also CosA = adjacent/hypotenuse

CosA = 6.9/12

CosA = 0.5750

Checking with your calculator or table of values A = 54.90 (approximately 55).

Finally TanA = opposite/adjacent

TanA = 9.8/6.9

TanA = 1.4203

Checking with your calculator or table of values A = 54.83 (approximately 55).

3 0

2 years ago

In which quadrant does O lie if the following statements are true:<br> cos 0 < 0 and cscO > 0

Olin [163]

Answer:

2nd quadrant.

Step-by-step explanation:

$\text{Given that,}~ \cos \theta < 0~ \text{and}~ \csc \theta > 0.}\\\\\text{So,}~\cos \theta ~ \text{is negative and}~ \csc \theta ~ \text{is positive.}\\\\\text{In Quadrant II, all other ratios are negative except}~ \sin \theta ~ \text{ and}~ \csc \theta.\\\\\text{Hence, the angle lies in the 2nd quadrant.}~$

5 0

1 year ago