Answer
Find out the how much fluid do i have to drink .
To prove
As given
![I\ need\ to\ drink\ 8\frac{2}{4}\ cups\ of\ water\ and\ 2\frac{1}{5}\ cups\ of\ milk\ every\ day.](https://tex.z-dn.net/?f=I%5C%20need%5C%20to%5C%20drink%5C%208%5Cfrac%7B2%7D%7B4%7D%5C%20cups%5C%20of%5C%20water%5C%20and%5C%202%5Cfrac%7B1%7D%7B5%7D%5C%20cups%5C%20of%5C%20milk%5C%20every%5C%20day.)
I.e
![I\ need\ to\ drink\ \frac{34}{4}\ cups\ of\ water\ and\ \frac{11}{5}\ cups\ of\ milk\ every\ day.](https://tex.z-dn.net/?f=I%5C%20need%5C%20to%5C%20drink%5C%20%5Cfrac%7B34%7D%7B4%7D%5C%20cups%5C%20of%5C%20water%5C%20and%5C%20%5Cfrac%7B11%7D%7B5%7D%5C%20cups%5C%20of%5C%20milk%5C%20every%5C%20day.)
Thus
![Total\ fluid\ i\ have\ to\ drink = \frac{34}{4} +\frac{11}{5}](https://tex.z-dn.net/?f=Total%5C%20fluid%5C%20i%5C%20have%5C%20to%5C%20drink%20%3D%20%5Cfrac%7B34%7D%7B4%7D%20%2B%5Cfrac%7B11%7D%7B5%7D)
L.C.M of (4,5) = 20
![Total\ fluid\ i\ have\ to\ drink = \frac{34\times 5+11\times 4}{20}](https://tex.z-dn.net/?f=Total%5C%20fluid%5C%20i%5C%20have%5C%20to%5C%20drink%20%3D%20%5Cfrac%7B34%5Ctimes%205%2B11%5Ctimes%204%7D%7B20%7D)
![Total\ fluid\ i\ have\ to\ drink = \frac{170+44}{20}](https://tex.z-dn.net/?f=Total%5C%20fluid%5C%20i%5C%20have%5C%20to%5C%20drink%20%3D%20%5Cfrac%7B170%2B44%7D%7B20%7D)
![Total\ fluid\ i\ have\ to\ drink = \frac{214}{20}](https://tex.z-dn.net/?f=Total%5C%20fluid%5C%20i%5C%20have%5C%20to%5C%20drink%20%3D%20%5Cfrac%7B214%7D%7B20%7D)
Simplify the above
![Total\ fluid\ i\ have\ to\ drink = \frac{107}{10}](https://tex.z-dn.net/?f=Total%5C%20fluid%5C%20i%5C%20have%5C%20to%5C%20drink%20%3D%20%5Cfrac%7B107%7D%7B10%7D)
.
In the decimal form
Therefore the total fulid i have to drink is 10.7 .
Answer:
On a coordinate plane, a triangle has points (negative 4, 3), (1, negative 2), (5, 3).
Step-by-step explanation:
This coordinate above gives us the best range of values
Answer:
![\angle BDA = 72^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BDA%20%3D%2072%5E%7B%5Ccirc%7D)
![\angle DAB = 36^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20DAB%20%3D%2036%5E%7B%5Ccirc%7D)
![\angle BDC = 108^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BDC%20%3D%20108%5E%7B%5Ccirc%7D)
![\angle BCD = 36^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BCD%20%3D%2036%5E%7B%5Ccirc%7D)
![\angle DBC = 36^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20DBC%20%3D%2036%5E%7B%5Ccirc%7D)
Step-by-step explanation:
Given
Required
Determine the missing angles
Since AB = AD, then:
--- Base angles of an isosceles triangle
Hence:
![\angle ABD = \angle BDA = 72^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20ABD%20%3D%20%5Cangle%20BDA%20%3D%2072%5E%7B%5Ccirc%7D)
--- angles in a triangle
![72^{\circ} + 72^{\circ} + \angle DAB = 180^{\circ}](https://tex.z-dn.net/?f=72%5E%7B%5Ccirc%7D%20%2B%2072%5E%7B%5Ccirc%7D%20%2B%20%5Cangle%20DAB%20%3D%20180%5E%7B%5Ccirc%7D)
![144^{\circ} + \angle DAB = 180^{\circ}](https://tex.z-dn.net/?f=144%5E%7B%5Ccirc%7D%20%2B%20%5Cangle%20DAB%20%3D%20180%5E%7B%5Ccirc%7D)
Collect Like Terms
![\angle DAB = 180^{\circ} - 144^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20DAB%20%3D%20180%5E%7B%5Ccirc%7D%20-%20144%5E%7B%5Ccirc%7D)
![\angle DAB = 36^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20DAB%20%3D%2036%5E%7B%5Ccirc%7D)
--- angle on a straight line
![72^{\circ} + \angle BDC = 180^{\circ}](https://tex.z-dn.net/?f=72%5E%7B%5Ccirc%7D%20%2B%20%5Cangle%20BDC%20%3D%20180%5E%7B%5Ccirc%7D)
![\angle BDC = 180^{\circ} - 72^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BDC%20%3D%20180%5E%7B%5Ccirc%7D%20-%2072%5E%7B%5Ccirc%7D)
![\angle BDC = 108^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BDC%20%3D%20108%5E%7B%5Ccirc%7D)
Since ABC is isosceles, then:
--- base angle of isosceles
![\angle BCD = 36^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BCD%20%3D%2036%5E%7B%5Ccirc%7D)
Lastly:
![\angle BCD + \angle BDC + \angle DBC = 180^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20BCD%20%2B%20%5Cangle%20BDC%20%2B%20%5Cangle%20DBC%20%3D%20180%5E%7B%5Ccirc%7D)
![36^{\circ} + 108^{\circ} + \angle DBC = 180^{\circ}](https://tex.z-dn.net/?f=36%5E%7B%5Ccirc%7D%20%2B%20108%5E%7B%5Ccirc%7D%20%2B%20%5Cangle%20DBC%20%3D%20180%5E%7B%5Ccirc%7D)
![\angle DBC = 180^{\circ} - 36^{\circ} - 108^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20DBC%20%3D%20180%5E%7B%5Ccirc%7D%20-%2036%5E%7B%5Ccirc%7D%20-%20108%5E%7B%5Ccirc%7D)
![\angle DBC = 36^{\circ}](https://tex.z-dn.net/?f=%5Cangle%20DBC%20%3D%2036%5E%7B%5Ccirc%7D)
<em>See attachment</em>
The standard form of the equation is 2x^2+16x+11