Answer: the correct option is A (A zero net force causes no change to an object's
motion.)
Explanation:
Force is a vector quantity that causes an object to accelerate or change velocity when pushed or pulled. While a NET FORCE can be defined as the combination of all forces acting on an object which is equally capable of accelerating the object.
When a NET FORCE is equal to zero( that is zero net force),there will be no change to an object's motion. When the net force of an object is equal to zero , it shows the object is in either static equilibrium( the objects velocity is zero) or dynamic equilibrium(where the object is moving at constant velocity). In both cases, the object remains motionless because the net forces is equal to zero.
This freezing point business is usually based on molality, that is moles solute per kilogram of solvent.
<span>molality = freezing point depression over Kf </span>
<span>In this case molality -10.3 degrees over -1.85 degrees Kf = 5.53 molal </span>
<span>This 5.53 molal solution is made up of l000 gms water and 5.53 moles glucose at 180 grams per mole for a total mass of 1997 grams </span>
<span>It volume would be l997 gms over 1.50 gms/ml or 1331 ml </span>
<span>We know that we have 5.53 moles of glucose dissolved in l331 ml of solution so now we can find how many moles of glucose in l000 ml or one liter of solution and this will be our Molarity </span>
<span>5.53 moles glucose over l331 ml = X moles glucose over l000 ml solution </span>
<span>cross multiply and solve for X moles glucose per liter solution </span>
<span>X = 4.15 moles glucose per liter = 4.15 Molar</span>
When the balanced reaction equation of methane combustion is:
CH4 + 2O2 →CO2 + 2H2O
so, we can see that each 1 mole of methane combusted will give 2 moles of water as a product.
so first, we need to get the moles of methane =
= mass of methane /molar mass of methane
= 52.6 g / 16.04 g/mol
= 3.28 moles
when 1 mol of methane produces→ 2 moles of water
∴ 3.28 moles methane produces → X moles of water
∴ moles of water = 3.28 * 2
= 6.56 moles
when each 1 mole of water has 6.02 x 10^23 (Avogadro's number ) individual molecules:
∴number of molecules of water = 6.56 * 6.02 x 10^23
= 3.9 x 10^24 molecules
B 0.146m
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