To
determine the volume of both concentration of the solution to make another concentration of solution, we need to set up
two equations since we have two unknowns. <span>
For the first equation, we do a mass balance:
mass of 50% solution + mass of 20% solution =
mass of 40% solution
M1 + M2 = M3
For the second equation, we do a component balance,</span>
<span>
M1(50%) + M2(20%) = M3(40%)
.50M1 + .20M2 = .40M3
To determine the ratio, we assume we have to make a 100 g of the 40% solution. So, the equation would change to</span>
<span>
</span>
<span>M1 + M2 = 100</span>
.50M1 + .20M2 = (100)(.40) = 40
Solving for M1 and M2,
M1 = 66.67 g
M2 = 33.33 g
So, the ratio of the 20% and the 50% would be approximately 33.33/66.67 = 0.5.
CaCO3 is the reactant in excess. The amount of CaCO3 remaining is 11.5 g . ... Hydrochloric acid and calcium chloride. 2 mol HCl1 CaCl2. Determine the mass of CaCO3 that reacted with the limiting reactant HCl .
Answer: Cyclohexene
Explanation:
Cyclohexane belongs to the Alkenes family. Alkenes react in the cold with pure liquid bromine, or with a solution of bromine in an organic solvent like tetrachloromethane. The double bond breaks, and a bromine atom get attached to each carbon. The bromine loses its original red-brown color to give a colorless liquid. In the case of the reaction with ethene, 1,2-dibromoethane is formed. When bromine is added to cyclohexane in the dark room, there won't be any reaction. If the mixture is exposed to light however, free bromine radicals are generated. In this condition, polybrominated products can be produced as well.
