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valkas [14]
2 years ago
15

Please help ASAP Read thing for the question thanks!!

Chemistry
1 answer:
katovenus [111]2 years ago
4 0

Answer:

JOSHUA

Explanation:

JOSHUA

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Electrochemistry - Equilibrium
Ipatiy [6.2K]

Answer:

Explanation:

The relation between equilibrium constant and Ecell is given below .

E⁰cell = (RT / nF ) lnK  , F is faraday constant T is 273 + 25 = 298 K

E⁰cell  =  1.46 - 1.21 = .25 V

n = 2

Putting the values

.25 = (8.314 x 298  lnK) / (2 x 96485 )

lnK = 19.47

K = 2.85 x 10⁸

2 )

Change in free energy Δ G

Δ G ⁰ = nE⁰ F

n = 4

E⁰ = .4 + .83 = 1.23 V

Δ G ⁰= 4 x 1.23 x 96485

= 474706 J / mol

3 )

E⁰cell = (RT / nF ) lnK

n = 2

1.78 = 8.314 x 298  lnK / 2 x 96485

lnK = 138.638

K = 1.62 x 10⁶⁰

8 0
3 years ago
In a typical analysis, 15 ml of an aqueous solution containing an unknown amount of acetylcholine had a ph of 7.65. When incubat
melomori [17]

pH of the acetyl choline solution before incubation = 7.65

[H_{3}O^{+}]=10^{-7.65}=2.24*10^{-8}M

pH of the solution after incubation = 6.87

[H_{3}O^{+}]=10^{-6.87}=1.35*10^{-7}M

The difference in concentration of hydronium ion before and after incubation

=1.35*10^{-7}M-2.24*10^{-8}M=1.126*10^{-7}M

This difference in hydronium ion concentration can be attributed to the increase in the concentration of acetic acid, which is formed when acetylcholine is hydrolyzed by acetycholinesterase. The mole ratio of acetylcholine to acetic acid is 1:1.

Therefore the moles of acetylcholine = 15 mL * \frac{1L}{1000mL}*\frac{1.126*10^{-7}mol }{L}=1.689*10^{-9}mol


7 0
3 years ago
How much carbon will turn into carbon 14 every year?<br><br> Science<br> Please help asap
saw5 [17]

Answer:

There are three naturally occurring isotopes of carbon on Earth: carbon-12, which makes up 99% of all carbon on Earth; carbon-13, which makes up 1%; and carbon-14, which occurs in trace amounts, making up about 1 or 1.5 atoms per 1012 atoms of carbon in the atmosphere.

Names: carbon-14, C-14, radiocarbon

Isotope mass: 14.003241 u

Half-life: 5,730 ± 40 years

Symbol: 14C

Explanation:

Pls give me brainliest

( ^ . ^ )

5 0
3 years ago
How many metres further would the sound intensity be 1/2 times as much as that at a distance of 3 m from an acoustic source?
marshall27 [118]

Solution :

Let, intensity at distance 3 m from the acoustic source is I_o.

We need to find the distance d where the intensity is \dfrac{I_o}{2}.

Now, we know intensity is inversely proportional to square of distance between the source.

\dfrac{I_o}{\dfrac{I_o}{2}} = \dfrac{d^2}{3^2}\\\\d^2 = 18 \\\\d = 3\sqrt{2}\ m

Therefore, intensity will be halved at a distance of 3\sqrt{2}\ m.

7 0
2 years ago
Jake put a bottle of water on the desk and left the room. When he came
fiasKO [112]

Answer:

The air in the room

Explanation:

The diffrent temp of the water compared to the room. The water was colder than the room.

4 0
3 years ago
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