EASY QUESTION WILL GIVE BRAINLIEST!!!

Could i get some help here please?

DENIUS [597]

Answer:

22+4x=90

x=17

Step-by-step explanation:

From the picture, we can see that the two angles form a right angle.

The equation will be 22+4x=90

Then use that equation to solve for x.

4x=68

x=17

4 0

2 years ago

Read 2 more answers

An online health and medicine company claims that about 50% of Internet users would go to an online sight first for information

olga55 [171]

Answer:

The p-value of the test is 0.0018, which means that for a level of significance higher than this, there is sufficient evidence to claim that less than 50% of Internet users get their health questions answered online.

Step-by-step explanation:

Test the claim that less than 50% of Internet users get their health questions answered online.

At the null hypothesis, we test that 50% of Internet users get their health questions answered online, that is:

$H_0: p = 0.5$

At the alternate hypothesis, we test that this proportion is less than 50%, that is:

$H_a: p < 0.5$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.5 is tested at the null hypothesis:

This means that $\mu = 0.5, \sigma = \sqrt{0.5*0.5} = 0.5$

A random sample of 1318 Internet users was asked where they will go for information the next time they need information about health or medicine; 606 said that they would use the Internet.

This means that $n = 1318, X = \frac{606}{1318} = 0.4598$

Test statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.4598 - 0.5}{\frac{0.5}{\sqrt{1318}}}$

$z = -2.92$

P-value of the test and decision:

The p-value of the test is the probability of finding a sample proportion below 0.4598, which is the p-value of z = -2.92.

Looking at the z-table, z = -2.92 has a p-value of 0.0018.

The p-value of the test is 0.0018, which means that for a level of significance higher than this, there is sufficient evidence to claim that less than 50% of Internet users get their health questions answered online.

8 0

3 years ago

NCAA stated that of the nearly 8,000,000 high school students participating in high school athletics, only 460,000 of those stud

Ilia_Sergeevich [38]

Answer:

0.5934% probability that a baseball player will play at an NCAA college and will also go on to be drafted by the MLB

Step-by-step explanation:

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$