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Tomtit [17]
3 years ago
8

Using Ohms Law, calculate the current that would exist in a circuit having a voltage of 240V experiencing 110 Ohms of resistance

Physics
1 answer:
anygoal [31]3 years ago
8 0

To find the Voltage, ( V ) [ V = I x R ] V (volts) = I (amps) x R (Ω)

To find the Current, ( I ) [ I = V ÷ R ] I (amps) = V (volts) ÷ R (Ω)

To find the Resistance, ( R ) [ R = V ÷ I ] R (Ω) = V (volts) ÷ I (amps)

To find the Power (P) [ P = V x I ] P (watts) = V (volts) x I (amps)

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Ingrid lives in a cold country, that sometimes gets a lot of snow. when that happens people can enjoy lot pf skiing. Ingrid goes
photoshop1234 [79]

Answer:

Because the surface area of her skis are greater than the surface are of her shoes

Explanation:

the reason for this is that the weight per in is too heavy crushing the snow blower but with the skies the weight is distributed to the point were the snow can support her weight

8 0
3 years ago
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.60 mm. If a
nata0808 [166]

Answer:

Explanation:

(a) For the calculation of the Electric field we use

E=\frac{V}{d}=\frac{15.0V}{1.6*10^{-3}m} =9375\frac{N}{C}

(b) The capacitance is calculate by using the expression

C=\frac{\epsilon_{0}A}{d}=\frac{8.85*10^{-12}C^{2}/(Nm^{2})*(7.6*10^{-4}m^{2})}{1.6*10^{-3}m}=4.2*10^{-12}C

(c) Finally, the charge on each plate is

Q=CV=(4.2*10^{-12}C)(15V)=6.3*10^{-11}C

I hope this is useful for you

Regards

4 0
3 years ago
Read 2 more answers
Urgent<br> Please write the complete answer
Crazy boy [7]

Multiply field strength (N/kg) by mass (kg) to get weight (N)

At the start, the car is carrying

4.7 kg * (9.8 N/kg) = 46.06 N

of fuel.

At the end, it is carrying

3.0 kg * (9.8 N/kg) = 29.4 N.

Assuming the car remains completely intact, its weight was reduced by

46.06 N - 29.4 N = 16.66 N.

5 0
4 years ago
Explain why surface tension occurs
Fynjy0 [20]
Hey there! <span>The cohesive forces between liquid molecules are responsible for the phenomenon known as </span>surface tension<span>. The molecules at the </span>surface do<span> not have other like molecules on all sides of them and consequently they cohere more strongly to those directly associated with them on the </span>surface<span>. Hope this helps! :)</span>
5 0
3 years ago
) A skier starts down a frictionless 32° slope. After a vertical drop of 25 m, the slope temporarily levels out and then slopes
EastWind [94]

Answer:

The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

Explanation:

Given that,

Slope down = 32°

Height = 25 m

Before leveling,

Slope down = 20°

Height = 38 m

We need to calculate the skier’s speed on the two level stretches

Using formula of energy

P.E=K.E

mgh=\dfrac{1}{2}mv^2

v=\sqrt{2gh}

For first stretch,

Height = 25 m

Put the value into the formula

v=\sqrt{2\times9.8\times25}

v=22.13\ m/s

For second stretch,

Height = 38 m

Put the value into the formula

v=\sqrt{2\times9.8\times38}

v=27.29\ m/s

Hence, The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

5 0
4 years ago
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