Question

) A skier starts down a frictionless 32° slope. After a vertical drop of 25 m, the slope temporarily levels out and then slopes down at 20°, dropping an additional 38 m vertically before leveling out again. Find the skier’s speed on the two level stretches

Answer 1

Answer:

The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.

Explanation:

Given that,

Slope down = 32°

Height = 25 m

Before leveling,

Slope down = 20°

Height = 38 m

We need to calculate the skier’s speed on the two level stretches

Using formula of energy

$P.E=K.E$

$mgh=\dfrac{1}{2}mv^2$

$v=\sqrt{2gh}$

For first stretch,

Height = 25 m

Put the value into the formula

$v=\sqrt{2\times9.8\times25}$

$v=22.13\ m/s$

For second stretch,

Height = 38 m

Put the value into the formula

$v=\sqrt{2\times9.8\times38}$

$v=27.29\ m/s$

Hence, The skier’s speed on the two level stretches are 22.13 m/s and 27.29 m/s.