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Marina CMI [18]
3 years ago
12

Solve: 0.2c + 0.69 = 1.37 c = _____

Mathematics
1 answer:
iVinArrow [24]3 years ago
5 0

Answer:

c = 3.4. I hope this is the answer:)

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A coordinate plane with a line passing through the points (negative 4, negative 5) and (1, negative 1).
Ksju [112]

Answer:

4x - 5y - 9 = 0

\frac{9}{4}

\frac{-9}{5}

Step-by-step explanation:

The equation of a straight line passing through the points (-4,-5) and (1,-1) is given by \frac{y - (-5)}{-5-(-1)} =\frac{x-(-4)}{-4-1}

⇒ \frac{y+5}{-4} =\frac{x+4}{-5}

⇒ 5y + 25 = 4x + 16

⇒ 4x - 5y - 9 = 0 ....(1) (Answer)

Now, this above equation can be represented as

\frac{x}{\frac{9}{4} } + \frac{y}{\frac{-9}{5} } =1

Therefore, the x-intercept is \frac{9}{4} (Answer)

And the y-intercept is \frac{-9}{5}. (Answer)

7 0
4 years ago
Read 2 more answers
A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.
tatyana61 [14]

Answer:

(a)g(n)=0.05\cdot 2^n

(b)g^{-1}(n)=\log_{2}20g(n)

(c)43 times

Step-by-step explanation:

<u>Part A</u>

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n

<u>Part B</u>

<u />g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)<u />

<u />

<u>Part C</u>

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

3 0
3 years ago
Density is mass divided by volume. Find the density of an aluminum block with a mass of 35 grams and a volume of 14 cm3?
castortr0y [4]
The answer is 2.5 g/cm 3 :)

6 0
4 years ago
Which of the following circles have their centers in the second quadrant? Check all that apply.
ivann1987 [24]
The given circles are given in standard form:
(x - xc)² + (y - yc)² = r²

The second quadrant is the one that has negative x coordinates and positive y coordinates.

This said, let's see all your options:
A) (x - 5)² + (y - 6)² = 25
xc = -(-5) = +5
yc = -(-6) = +6
C (5 , 6) is in the first quadrant.

B) (x + 1)² + (y - 7)² = 16
xc = -(+1) = -1
yc = -(-7) = +7
C (-1 , 7) is in the second quadrant.

C) (x - 4)² + (y + 3)² = 32
xc = -(-4) = +4
yc = -(+3) = -3
C (4, -3) is in the fourth quadrant.

<span> D) (x + 2)² + (y - 5)²= 9</span>
xc = -(+2) = -2
yc = -(-5) = +5
C (-2 , +5) is in the second quadrant.

Therefore, the correct answers are B and D.
7 0
4 years ago
What is the answer to |x-4|&lt;13
VARVARA [1.3K]

Answer:

<h2>The solution is -9 < x < 17.</h2>

Step-by-step explanation:

|x-4|<13.

The above equation means, whatever the actual value of x is, the value of (x - 4) must be greater than - 13 and less than 13.

Hence, -13 < x - 4 < 13 or, -9 < x < 17. The value of x will be in between -9 and 17. The value of x can not be -9 or 17.

7 0
3 years ago
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