Answer:
Explanation:
The reasons why a language would distinguish between uppercase and lowercase in its identifiers are:
(1) So that variable identifiers may look different than identifiers that are names for constants, such as the convention of using uppercase for constant names and using lowercase for variable names in C.
(2) So that the catenated words such as names can have their first letter distinguished, as in Total Words. The primary reason why a language would not distinguish between uppercase and lowercase in identifiers is it makes programs less readable, because words that look very similar are actually completely different, such as SUM and Sum.
Answer:
Al hablar de entornos digitales de enseñanza y aprendizaje, la frase apunta al avenimiento de medios informáticos y tecnológicos al proceso metodológico de enseñanza de los distintos sistemas educativos a nivel mundial.
Así, la irrupción del internet como medio de búsqueda de información y las herramientas digitales como vídeos, diapositivas y libros electrónicos como métodos de presentación de información han facilitado el acceso de los alumnos y docentes al conocimiento a través de la generación de un entorno digital que permite a estos un acceso mas rápido y abarcativo al conocimiento.
anything
Explanation:
I know what to say this time
Answer:
Explanation:
d(x) = -2x - 6
to find the inverse of a function, you need to follow these steps:
1. set d(x) = y
2. interchange the variables, so y becomes x and x becomes y
3. solve the equation for y
<u>step 1:</u> set d(x) = y
y = -2x -6
<u>step 2:</u> interchanging the variables
y = -2x - 6 turns into x = -2y - 6
<u>step 3:</u> solving for y
x = -2y - 6 < add 6 to both sides to get rid of it on the right
x + 6 = -2y < divide both sides by -2 to get y alone
x + 6 / -2 =
-2y / -2 = y
= y
so the inverse of the function is
Answer:
In Java:
import java.util.*;
public class Main{
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
String isbn;
System.out.print("First 1:2 digits: ");
isbn = input.nextLine();
if(isbn.length()==12){
int chksum = 0;
for(int i = 0; i<12;i++){
if((i+1)%2==0){ chksum+= 3 * Character.getNumericValue(isbn.charAt(i)); }
else{ chksum+=Character.getNumericValue(isbn.charAt(i)); } }
chksum%=10;
chksum=10-chksum;
if(chksum==10){
System.out.print("The ISBN-13 number is "+isbn+"0");}
else{
System.out.print("The ISBN-13 number is "+isbn+""+chksum); } }
else{
System.out.print("Invalid Input");
} }}
Explanation:
See attachment for explanation where comments are used to explain each line
